Box-girder bridge, layout of the longitudinal prestress to SIA 262

The code governs which inputs appear and how every value is derived.

Member

Material properties, shared by every verification. The cross-section is not shared: SIA 262 works from the section as sized for each internal-force case, so it belongs to each verification and appears with it.

About this check

clauses, worked example and questions

Places the longitudinal tendons of a continuous box girder to SIA 262:2025: the ducts in the webs with their cover and spacing, the profile along all the spans with the minimum radius, optional couplers, and the anchors at the ends of the bridge. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You enter the spans and the two cross-sections, as in the predimensioning module, then the covers cnom and cnom,p, the bar diameters and Dmax. For the tendons: fpk, fp0,1k, Ap1, ns, the duct diameter Ød, the tendons in each web, the ducts side by side and their clear spacings. For the profile: the height of the anchors yE, the low point ξ of the end spans, Rmin and the construction, continuous tendons or span-by-span with couplers. Then the anchor data from the approval, the end block width ba, γP and the interval Δx of the coordinate table.

You get the duct arrangement, the profile span by span, the anchor layout with a pass or fail for each check, and a table of the coordinates x, y, z of every duct axis along the bridge.

Assumptions and limits

Worked example

The three-span girder of 36, 45 and 36 m, 2,400 mm deep, with five tendons of 19 strands in each web, two ducts of 100 mm side by side, cnom = 40 mm, yE = 1,300 mm, Rmin = 6.5 m, continuous tendons and two anchors side by side in an end block 1,000 mm wide. Every check passes. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Number of spans n3
Span lengthsEnd spans alike, interior spans alike
End spans le36 m
Interior spans li45 m
Cross-section along the bridgeA thicker section over the interior supports
Width of the deck B12.5 m
Depth of the girder h2400 mm
Thickness of the top slab tt280 mm
Length of each cantilever bc3.0 m
Thickness of a web bw450 mm
Width of the bottom slab binf5.0 m
Thickness of the bottom slab tb250 mm
Thickness of the top slab tt,s280 mm
Thickness of a web bw,s550 mm
Thickness of the bottom slab tb,s450 mm
Length of this section on each side of a support ls8 m
Cover of the reinforcement cnom40 mm§ 5.2.2.4
Cover required for the prestressing units cnom,p50 mm§ 5.2.2.4
Diameter of the transverse bars and stirrups Øt16 mm
Diameter of the longitudinal bars Øl16 mm
Maximum aggregate size Dmax32 mm
Tensile strength of the prestressing steel fpk1860 N/mm²
Proof stress of the prestressing steel fp0,1k1640 N/mm²
Area of one strand Ap1150 mm²
Strands per tendon ns19
Outer diameter of a duct Ød100 mm
Tendons in each web nt5
Ducts side by side across the web nc2
Clear spacing between ducts side by side sh60 mm
Clear spacing between rows of ducts sv60 mm
Height of the anchors at the ends of the bridge yE1300 mm
Low point in the end spans, from the end support ξ0.4
Minimum radius of the tendon Rmin6.5 m
Tendons and constructionTendons continuous from one end of the bridge to the other
Side of an anchor plate apl300 mm
Minimum centre spacing of anchors sa,min440 mm
Minimum distance from an anchor axis to an edge ra,min270 mm
Anchors side by side in each web nc,a2
Centre spacing of the anchors sa450 mm
Width of the end block of each web ba1000 mm
Load factor of the prestress for the anchorage zones γP1.2§ 4.1.5.5.3
Interval between the stations along the bridge Δx1 m
Calculation: The bridge
StepValueRef.
Total length2·le + (n − 2)·liL = 117.00 m
Calculation: The two cross-sections
StepValueRef.
Inclination of the websfrom the verticalβw = 19.5 °
Cover of the ductscnom + Øt + Ølfrom any face to the nearest duct: the stirrups or transverse bars, then the longitudinal bars, lie outside the ductscd = 72 mm
Step1In the spans2Over the supportsls = 8.0 m each sideRef.
Area Ac m²outline minus the cell6.4557.659
Height of the centroid yG mmabove the bottom face1,5591,410
Web thickness square to the web bw⊥ mmbw·cos βw424519
Calculation: Tendons
StepValueRef.
Area of one tendonns·Ap1Ap,t = 2,850 mm²
Largest stress at stressingmin(0.75·fpk; 0.85·fp0,1k)immediately after stressing, before the lossesσp0 = 1,394 N/mm²§ 4.1.5.2.2 (22)
Force of one tendon at stressingAp,t·σp0P0 = 3,973 kN
Calculation: Cover of the ducts
StepValueRef.
Cover of the ducts at least half their diameterØd/2 ≤ cdη = 0.694 · Pass69 % of the capacity used§ 5.2.2.2
Cover of the ducts at least the maximum aggregate sizeDmax ≤ cdη = 0.444 · Pass44 % of the capacity used§ 5.2.2.2
Cover of the ducts for the exposure classcnom,p ≤ cdη = 0.694 · Pass69 % of the capacity used§ 5.2.2.4
Calculation: Clear spacing of the ducts
StepValueRef.
Smallest clear spacing allowedmax(Dmax; Øl; 20 mm)smin = 32 mm§ 5.2.3.2
Clear spacing of the ducts side by sidesmin ≤ shη = 0.533 · Pass53 % of the capacity used§ 5.2.3.2
Clear spacing of the rows of ductssmin ≤ svη = 0.533 · Pass53 % of the capacity used§ 5.2.3.2
Calculation: Ducts in each web at mid-span
StepValueRef.
Rows of ducts⌈nt/nc⌉the last row, the highest, holds 1nr = 3
Height of the centroid of the ductsmean of the duct centres; the lowest row at cd + Ød/2, the rows (Ød + sv) apartabove the bottom face; dp = h − yp,f = 2,150 mmyp,f = 250 mm
Web thickness needed2·cd + nc·Ød + (nc − 1)·shbw,req = 404 mm
The ducts fit in the web of the span sectionbw,req ≤ bw⊥η = 0.952 · Pass95 % of the capacity used§ 5.3.1
Calculation: Ducts in each web over the supports
StepValueRef.
Depth of the centroid of the ducts below the top facethe same arrangement, the highest row at cd + Ød/2 from the top faceheight above the bottom face yp,s = 2,150 mmdp,s = 250 mm
The ducts fit in the web of the support sectionbw,req ≤ bw⊥η = 0.779 · Pass78 % of the capacity used§ 5.3.1
Tendons in the bridge2·ntin the two websnT = 10
Prestressing steel in the section2·nt·Ap,tAp = 28,500 mm²
Force of all the tendons at stressingnT·P0ΣP0 = 39.73 MN
Calculation: Key heights of the resultant tendon
StepValueRef.
At the anchors, ends of the bridgeeccentricity 259 mm below the centroidyE = 1,300 mm
At the low pointsfrom part 2yp,f = 250 mm
Over the interior supportsfrom part 2yp,s = 2,150 mm
Eccentricity at the low pointsyG − yp,fbelow the centroidef = 1,309 mm
Eccentricity over the supportsyp,s − yG,sabove the centroides = 740 mm
Calculation: The profile span by span
Step1Span 1l = 36.0 m2Span 2l = 45.0 m3Span 3l = 36.0 mRef.
Low point from the left support xm mξ·le in the end spans, l/2 elsewhere14.4022.5021.60
Reverse curve at the left support aL m2·(yp,s − yp,f)·Rmin/D·1.101.14
Reverse curve at the right support aR mD: from the support to the low point1.141.10·
Smallest radius in the span Rf mD·(D − a)/(2·Δy); D²/(2·Δy) towards an end support98.7126.798.7
Steepest slope θmax °atan(2·Δy/D), at the inflection points and the anchors9.989.599.98
Angular deviation along the span Σ|Δθ| radsum of the changes of slope0.4930.6680.493
Calculation: Radius of the tendon
StepValueRef.
Radius over the interior supports= Rmin by the choice of aRs = 6.50 m
Smallest radius in the spans not below the minimum radiusRmin ≤ Rfη = 0.066 · Pass7 % of the capacity used
Angular deviation from one end to the otherneeded for the friction lossesΣ|Δθ| = 1.654 rad
Calculation: Forces at the anchors
StepValueRef.
Force of one tendon at stressingAp,t·σp0P0 = 3,973 kN
Design force for the anchorage zone, per anchorγP·P0Pd = 4,767 kN§ 4.1.5.5.3
Design force in the end block of a webnt·PdΣPd = 23.84 MN
Calculation: Anchors in the end block of each web
StepValueRef.
Rows of anchors⌈nt/nc,a⌉centred on yEnr,a = 3
Lowest and highest anchor axisabove the bottom faceya = 940 to 1,840 mm
Centre spacing of the anchorssa,min ≤ saη = 0.978 · Pass98 % of the capacity used
The anchor plates do not overlapapl ≤ saη = 0.667 · Pass67 % of the capacity used
Width of the end blockba,req ≤ baη = 0.990 · Pass99 % of the capacity used
Distance of the lowest anchor to the bottom facera,min ≤ ya,lowη = 0.287 · Pass29 % of the capacity used
Distance of the highest anchor to the top facera,min ≤ h − ya,highη = 0.482 · Pass48 % of the capacity used
Calculation: Each tendon of a web
StepValueRef.
Smallest radius of every tendon not below the minimum radiusRmin ≤ Rmin,iη = 0.088 · Pass9 % of the capacity used
Clear distance between the ducts all along the bridgesmin ≤ sclearη = 0.533 · Pass53 % of the capacity used§ 5.2.3.2
Step1Tendon 12Tendon 23Tendon 34Tendon 45Tendon 5Ref.
Height at the anchors zE mmthe anchor of the same rank9409401,3901,3901,840
Height at the low points zf mmits duct at mid-span122122282282442
Height over the interior supports zs mmsame column, order kept1,9582,1182,1182,2782,278
Offset across the web at mid-span u mmtowards the outer face positive80-8080-8080
Offset across the web at the anchors uE mm225-225225-2250
Reverse curve over the first interior support a m2·(zs − zf)·Rmin/D1.111.201.111.201.11
Smallest radius Rmin,i m120.6110.493.693.674.2
Calculation: Coordinates of the tendons
StepValueRef.
Stationsfrom x = 0 at the first end support to x = 117.00 m at the lastnx = 118
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How this module is verified

Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.

Questions

Why is the web thickness taken square to the web?

The webs are inclined, and the ducts need the thickness measured square to them: bw⊥ = bw·cos βw. In the worked example the span section needs 404 mm, η = 0.952.

What is the angular deviation used for?

For the friction losses. In the worked example it is 1.654 rad from one end of the bridge to the other.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 262:2025 · Page updated: 8 November 2026