Places the longitudinal tendons of a continuous box girder to SIA 262:2025: the ducts in the webs with their cover and spacing, the profile along all the spans with the minimum radius, optional couplers, and the anchors at the ends of the bridge. Every step shows its formula and the clause it comes from.
What it checks
- Cross-sections: Ac, yG, the inclination of the webs βw and the web thickness square to the web bw⊥ = bw·cos βw.
- Tendons: Ap,t = ns·Ap1, the largest stress at stressing σp0 = min(0.75·fpk; 0.85·fp0,1k), clause 4.1.5.2.2, equation (22), and the force P0 = Ap,t·σp0.
- Cover of the ducts: cd = cnom + Øt + Øl, with cd ≥ Ød/2 and cd ≥ Dmax (clause 5.2.2.2), and cd ≥ cnom,p (clause 5.2.2.4).
- Clear spacing: sh and sv ≥ smin = max(Dmax; Øl; 20 mm), clause 5.2.3.2.
- Ducts in each web, at mid-span and over the supports: the rows nr = ⌈nt/nc⌉, the centroid yp,f and dp,s, and bw,req = 2·cd + nc·Ød + (nc − 1)·sh ≤ bw·cos βw, clause 5.3.1.
- Profile of the resultant tendon: the eccentricities ef and es, and span by span the low point xm, the reverse curves aL and aR, the smallest radius Rf, the steepest slope θmax and the angular deviation Σ|Δθ|. Check: Rf ≥ Rmin.
- Anchors: Pd = γP·P0 per anchor, clause 4.1.5.5.3, and ΣPd per web. Checks: sa ≥ sa,min, sa ≥ apl, (nc,a − 1)·sa + 2·ra,min ≤ ba, and the distances of the lowest and highest anchors to the faces against ra,min.
- Every tendon: its heights zE, zf and zs, its offsets u and uE across the web, its smallest radius Rmin,i ≥ Rmin, and the clear distance between the ducts all along the bridge, checked every 0.25 m against clause 5.2.3.2.
What you enter and what you get
You enter the spans and the two cross-sections, as in the predimensioning module, then the covers cnom and cnom,p, the bar diameters and Dmax. For the tendons: fpk, fp0,1k, Ap1, ns, the duct diameter Ød, the tendons in each web, the ducts side by side and their clear spacings. For the profile: the height of the anchors yE, the low point ξ of the end spans, Rmin and the construction, continuous tendons or span-by-span with couplers. Then the anchor data from the approval, the end block width ba, γP and the interval Δx of the coordinate table.
You get the duct arrangement, the profile span by span, the anchor layout with a pass or fail for each check, and a table of the coordinates x, y, z of every duct axis along the bridge.
Assumptions and limits
- The same tendons run along the whole bridge, half in each web. They keep their column and order, so they do not cross.
- Each interior span: a parabola down from the support with the radius Rmin, an inflection point, a parabola through the low point. Towards an end support a single parabola rises to the anchors.
- Spacing and edge distances follow the approval of the prestressing system; anchors at the joints of a span-by-span construction need the same room.
- The anchorage zone must carry Pd into the girder: a strut-and-tie model with the concrete tension neglected, and always a minimum reinforcement against cracking (clause 5.3.2).
Worked example
The three-span girder of 36, 45 and 36 m, 2,400 mm deep, with five tendons of 19 strands in each web, two ducts of 100 mm side by side, cnom = 40 mm, yE = 1,300 mm, Rmin = 6.5 m, continuous tendons and two anchors side by side in an end block 1,000 mm wide. Every check passes. These are the module's own results for its worked example, computed when this page was built.
Inputs| Input | Value | Ref. |
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| Number of spans n | 3 | |
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| Span lengths | End spans alike, interior spans alike | |
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| End spans le | 36 m | |
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| Interior spans li | 45 m | |
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| Cross-section along the bridge | A thicker section over the interior supports | |
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| Width of the deck B | 12.5 m | |
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| Depth of the girder h | 2400 mm | |
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| Thickness of the top slab tt | 280 mm | |
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| Length of each cantilever bc | 3.0 m | |
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| Thickness of a web bw | 450 mm | |
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| Width of the bottom slab binf | 5.0 m | |
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| Thickness of the bottom slab tb | 250 mm | |
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| Thickness of the top slab tt,s | 280 mm | |
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| Thickness of a web bw,s | 550 mm | |
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| Thickness of the bottom slab tb,s | 450 mm | |
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| Length of this section on each side of a support ls | 8 m | |
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| Cover of the reinforcement cnom | 40 mm | § 5.2.2.4 |
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| Cover required for the prestressing units cnom,p | 50 mm | § 5.2.2.4 |
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| Diameter of the transverse bars and stirrups Øt | 16 mm | |
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| Diameter of the longitudinal bars Øl | 16 mm | |
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| Maximum aggregate size Dmax | 32 mm | |
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| Tensile strength of the prestressing steel fpk | 1860 N/mm² | |
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| Proof stress of the prestressing steel fp0,1k | 1640 N/mm² | |
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| Area of one strand Ap1 | 150 mm² | |
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| Strands per tendon ns | 19 | |
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| Outer diameter of a duct Ød | 100 mm | |
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| Tendons in each web nt | 5 | |
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| Ducts side by side across the web nc | 2 | |
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| Clear spacing between ducts side by side sh | 60 mm | |
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| Clear spacing between rows of ducts sv | 60 mm | |
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| Height of the anchors at the ends of the bridge yE | 1300 mm | |
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| Low point in the end spans, from the end support ξ | 0.4 | |
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| Minimum radius of the tendon Rmin | 6.5 m | |
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| Tendons and construction | Tendons continuous from one end of the bridge to the other | |
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| Side of an anchor plate apl | 300 mm | |
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| Minimum centre spacing of anchors sa,min | 440 mm | |
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| Minimum distance from an anchor axis to an edge ra,min | 270 mm | |
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| Anchors side by side in each web nc,a | 2 | |
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| Centre spacing of the anchors sa | 450 mm | |
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| Width of the end block of each web ba | 1000 mm | |
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| Load factor of the prestress for the anchorage zones γP | 1.2 | § 4.1.5.5.3 |
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| Interval between the stations along the bridge Δx | 1 m | |
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Calculation: The bridge| Step | Value | Ref. |
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| Total length2·le + (n − 2)·li | L = 117.00 m | |
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Calculation: The two cross-sections| Step | Value | Ref. |
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| Inclination of the websfrom the vertical | βw = 19.5 ° | |
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| Cover of the ductscnom + Øt + Ølfrom any face to the nearest duct: the stirrups or transverse bars, then the longitudinal bars, lie outside the ducts | cd = 72 mm | |
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| Step | 1In the spans | 2Over the supportsls = 8.0 m each side | Ref. |
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| Area Ac m²outline minus the cell | 6.455 | 7.659 | |
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| Height of the centroid yG mmabove the bottom face | 1,559 | 1,410 | |
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| Web thickness square to the web bw⊥ mmbw·cos βw | 424 | 519 | |
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Calculation: Tendons| Step | Value | Ref. |
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| Area of one tendonns·Ap1 | Ap,t = 2,850 mm² | |
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| Largest stress at stressingmin(0.75·fpk; 0.85·fp0,1k)immediately after stressing, before the losses | σp0 = 1,394 N/mm² | § 4.1.5.2.2 (22) |
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| Force of one tendon at stressingAp,t·σp0 | P0 = 3,973 kN | |
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Calculation: Cover of the ducts| Step | Value | Ref. |
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| Cover of the ducts at least half their diameterØd/2 ≤ cd | η = 0.694 · Pass69 % of the capacity used | § 5.2.2.2 |
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| Cover of the ducts at least the maximum aggregate sizeDmax ≤ cd | η = 0.444 · Pass44 % of the capacity used | § 5.2.2.2 |
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| Cover of the ducts for the exposure classcnom,p ≤ cd | η = 0.694 · Pass69 % of the capacity used | § 5.2.2.4 |
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Calculation: Clear spacing of the ducts| Step | Value | Ref. |
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| Smallest clear spacing allowedmax(Dmax; Øl; 20 mm) | smin = 32 mm | § 5.2.3.2 |
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| Clear spacing of the ducts side by sidesmin ≤ sh | η = 0.533 · Pass53 % of the capacity used | § 5.2.3.2 |
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| Clear spacing of the rows of ductssmin ≤ sv | η = 0.533 · Pass53 % of the capacity used | § 5.2.3.2 |
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Calculation: Ducts in each web at mid-span| Step | Value | Ref. |
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| Rows of ducts⌈nt/nc⌉the last row, the highest, holds 1 | nr = 3 | |
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| Height of the centroid of the ductsmean of the duct centres; the lowest row at cd + Ød/2, the rows (Ød + sv) apartabove the bottom face; dp = h − yp,f = 2,150 mm | yp,f = 250 mm | |
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| Web thickness needed2·cd + nc·Ød + (nc − 1)·sh | bw,req = 404 mm | |
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| The ducts fit in the web of the span sectionbw,req ≤ bw⊥ | η = 0.952 · Pass95 % of the capacity used | § 5.3.1 |
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Calculation: Ducts in each web over the supports| Step | Value | Ref. |
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| Depth of the centroid of the ducts below the top facethe same arrangement, the highest row at cd + Ød/2 from the top faceheight above the bottom face yp,s = 2,150 mm | dp,s = 250 mm | |
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| The ducts fit in the web of the support sectionbw,req ≤ bw⊥ | η = 0.779 · Pass78 % of the capacity used | § 5.3.1 |
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| Tendons in the bridge2·ntin the two webs | nT = 10 | |
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| Prestressing steel in the section2·nt·Ap,t | Ap = 28,500 mm² | |
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| Force of all the tendons at stressingnT·P0 | ΣP0 = 39.73 MN | |
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Calculation: Key heights of the resultant tendon| Step | Value | Ref. |
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| At the anchors, ends of the bridgeeccentricity 259 mm below the centroid | yE = 1,300 mm | |
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| At the low pointsfrom part 2 | yp,f = 250 mm | |
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| Over the interior supportsfrom part 2 | yp,s = 2,150 mm | |
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| Eccentricity at the low pointsyG − yp,fbelow the centroid | ef = 1,309 mm | |
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| Eccentricity over the supportsyp,s − yG,sabove the centroid | es = 740 mm | |
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Calculation: The profile span by span| Step | 1Span 1l = 36.0 m | 2Span 2l = 45.0 m | 3Span 3l = 36.0 m | Ref. |
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| Low point from the left support xm mξ·le in the end spans, l/2 elsewhere | 14.40 | 22.50 | 21.60 | |
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| Reverse curve at the left support aL m2·(yp,s − yp,f)·Rmin/D | · | 1.10 | 1.14 | |
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| Reverse curve at the right support aR mD: from the support to the low point | 1.14 | 1.10 | · | |
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| Smallest radius in the span Rf mD·(D − a)/(2·Δy); D²/(2·Δy) towards an end support | 98.7 | 126.7 | 98.7 | |
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| Steepest slope θmax °atan(2·Δy/D), at the inflection points and the anchors | 9.98 | 9.59 | 9.98 | |
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| Angular deviation along the span Σ|Δθ| radsum of the changes of slope | 0.493 | 0.668 | 0.493 | |
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Calculation: Radius of the tendon| Step | Value | Ref. |
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| Radius over the interior supports= Rmin by the choice of a | Rs = 6.50 m | |
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| Smallest radius in the spans not below the minimum radiusRmin ≤ Rf | η = 0.066 · Pass7 % of the capacity used | |
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| Angular deviation from one end to the otherneeded for the friction losses | Σ|Δθ| = 1.654 rad | |
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Calculation: Forces at the anchors| Step | Value | Ref. |
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| Force of one tendon at stressingAp,t·σp0 | P0 = 3,973 kN | |
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| Design force for the anchorage zone, per anchorγP·P0 | Pd = 4,767 kN | § 4.1.5.5.3 |
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| Design force in the end block of a webnt·Pd | ΣPd = 23.84 MN | |
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Calculation: Anchors in the end block of each web| Step | Value | Ref. |
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| Rows of anchors⌈nt/nc,a⌉centred on yE | nr,a = 3 | |
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| Lowest and highest anchor axisabove the bottom face | ya = 940 to 1,840 mm | |
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| Centre spacing of the anchorssa,min ≤ sa | η = 0.978 · Pass98 % of the capacity used | |
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| The anchor plates do not overlapapl ≤ sa | η = 0.667 · Pass67 % of the capacity used | |
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| Width of the end blockba,req ≤ ba | η = 0.990 · Pass99 % of the capacity used | |
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| Distance of the lowest anchor to the bottom facera,min ≤ ya,low | η = 0.287 · Pass29 % of the capacity used | |
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| Distance of the highest anchor to the top facera,min ≤ h − ya,high | η = 0.482 · Pass48 % of the capacity used | |
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Calculation: Each tendon of a web| Step | Value | Ref. |
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| Smallest radius of every tendon not below the minimum radiusRmin ≤ Rmin,i | η = 0.088 · Pass9 % of the capacity used | |
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| Clear distance between the ducts all along the bridgesmin ≤ sclear | η = 0.533 · Pass53 % of the capacity used | § 5.2.3.2 |
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| Step | 1Tendon 1 | 2Tendon 2 | 3Tendon 3 | 4Tendon 4 | 5Tendon 5 | Ref. |
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| Height at the anchors zE mmthe anchor of the same rank | 940 | 940 | 1,390 | 1,390 | 1,840 | |
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| Height at the low points zf mmits duct at mid-span | 122 | 122 | 282 | 282 | 442 | |
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| Height over the interior supports zs mmsame column, order kept | 1,958 | 2,118 | 2,118 | 2,278 | 2,278 | |
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| Offset across the web at mid-span u mmtowards the outer face positive | 80 | -80 | 80 | -80 | 80 | |
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| Offset across the web at the anchors uE mm | 225 | -225 | 225 | -225 | 0 | |
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| Reverse curve over the first interior support a m2·(zs − zf)·Rmin/D | 1.11 | 1.20 | 1.11 | 1.20 | 1.11 | |
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| Smallest radius Rmin,i m | 120.6 | 110.4 | 93.6 | 93.6 | 74.2 | |
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Calculation: Coordinates of the tendons| Step | Value | Ref. |
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| Stationsfrom x = 0 at the first end support to x = 117.00 m at the last | nx = 118 | |
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| — | |
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How this module is verified
Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.
Questions
Why is the web thickness taken square to the web?
The webs are inclined, and the ducts need the thickness measured square to them: bw⊥ = bw·cos βw. In the worked example the span section needs 404 mm, η = 0.952.
What is the angular deviation used for?
For the friction losses. In the worked example it is 1.654 rad from one end of the bridge to the other.
Can I print the calculation?
The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.
Related
Norm: SIA 262:2025 · Page updated: 8 November 2026