Sizes a continuous box girder of constant depth to SIA 262:2025, with one cross-section or a thicker one over the supports: the section properties, the actions with load model 1 of SIA 261, the design moments of the continuous girder and the first prestress by the force couple. Every step shows its formula and the clause it comes from.
What it checks
- The bridge: L = 2·le + (n − 2)·li, the ratio le/li and the slenderness l/h. Box girders of constant depth commonly lie between about 16 and 25.
- Cross-sections, in the spans and over the supports: Ac, yG, Ic, Wt, Wb, the efficiency ρ = Ic/(Ac·yt·yb), the self-weight g1 = γ·Ac, the ratio Ic,s/Ic,f and the inclination of the webs βw.
- Permanent loads: g2 = g2,e + g2,b + g2,r, with the surfacing g2,r = Br·er·γr.
- Road traffic: qk = αq·(Σ qk,i·wl + qkr·br) on the whole carriageway, and Qk = αQ·Σ 2·Qk,i, two axles 1.2 m apart in each lane.
- Design moments of the continuous girder: Mg, Mq on the spans that make it largest, MQ with the tandems at the worst position, and Md = γG·Mg + γQ·(Mq + MQ).
- Quick estimates: an interior span fixed at both ends, and a first prestressing steel Ap,est = |Mg,k|/(z·fpd) with z = 0.8·h.
- Design strengths: fcd = ηfc·ηt·fck/γc, clause 2.4.2.3, equation (2); fsd = fyk/γs, equation (4), and fpd = fp0,1k/γs, equation (5), clause 2.4.2.5.
- Effective widths of the compressed slabs, clause 4.1.3.3.2, equations (19) and (20), with l0 from clause 4.1.3.3.3.
- Prestress at mid-span of each span and over the first interior support, clause 4.1.5.5.1: Ap,req = (Md − As·fsd·zs)/(fpd·zp), the tendons needed 2·⌈nreq/(2·ns)⌉, and Md ≤ MRd = Ap·fpd·zp + As·fsd·zs.
- Ductility: x/dp ≤ 0.5·435/fyd, clause 4.1.4.2.6.
What you enter and what you get
You enter the number of spans, le and li, the outline of the box (B, h, bc, binf) with the thicknesses tt, bw and tb in the spans, and optionally thicker ones over the interior supports over a length ls. Then the materials and resistance factors, the edge beams, barriers and surfacing, the lanes of load model 1, γG and γQ. For the prestress: the height of the tendons at mid-span and over the supports, optional bars in the tension chord, the strands per tendon and the tendons chosen.
You get the loads, the moments along the girder, the tendons needed and the resistance of the couple at each key section, with the utilisation of each check and a pass or fail.
Assumptions and limits
- A continuous girder on rigid supports that do not settle. The end spans are alike, the interior spans are alike.
- Linear elastic analysis with the uncracked stiffness of each section, clause 4.1.4.1. The change of section is taken as a step.
- Haunches and the thinning of the cantilevers are not drawn: the thicknesses are mean values.
- The traffic is the leading action. Temperature, settlements and wind are left out; the prestress is part of the resistance. Its secondary moments are added later in the design.
- With x/d ≤ 0.35·435/fyd, steel of ductility class B or C and concrete up to C50/60, moments may be redistributed without checking the deformation capacity (clause 4.1.4.2.5).
Worked example
Three spans of 36, 45 and 36 m, a deck 12.5 m wide and a girder 2,400 mm deep, thicker over 8 m on each side of the interior supports, fck = 40 N/mm², three notional lanes of 3 m, and tendons of 19 strands: 6 at mid-span and 10 over the supports. Every check passes. These are the module's own results for its worked example, computed when this page was built.
Inputs| Input | Value | Ref. |
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| Number of spans n | 3 | |
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| Span lengths | End spans alike, interior spans alike | |
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| End spans le | 36 m | |
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| Interior spans li | 45 m | |
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| Cross-section along the bridge | A thicker section over the interior supports | |
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| Width of the deck B | 12.5 m | |
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| Depth of the girder h | 2400 mm | |
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| Thickness of the top slab tt | 280 mm | |
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| Length of each cantilever bc | 3.0 m | |
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| Thickness of a web bw | 450 mm | |
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| Width of the bottom slab binf | 5.0 m | |
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| Thickness of the bottom slab tb | 250 mm | |
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| Thickness of the top slab tt,s | 280 mm | |
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| Thickness of a web bw,s | 550 mm | |
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| Thickness of the bottom slab tb,s | 450 mm | |
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| Length of this section on each side of a support ls | 8 m | |
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| Characteristic compressive strength fck | 40 N/mm² | |
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| Unit weight of the reinforced concrete γ | 25 kN/m³ | |
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| Yield strength of the reinforcing steel fyk | 500 N/mm² | |
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| Proof stress of the prestressing steel fp0,1k | 1500 N/mm² | |
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| Area of one strand Ap1 | 150 mm² | |
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| Resistance factor for concrete γc | 1.5 | § 2.4.2.6 |
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| Resistance factor for steel γs | 1.15 | § 2.4.2.6 |
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| Duration factor ηt | 1.0 — both conditions of 4.2.1.3 met | § 4.2.1.3 |
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| Edge beams and parapets, both sides g2,e | 10 kN/m | |
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| Safety barriers, both sides g2,b | 2 kN/m | |
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| Width of the surfacing Br | 10.5 m | |
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| Thickness of the surfacing er | 100 mm | |
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| Unit weight of the surfacing γr | 24 kN/m³ | |
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| Width of a notional lane wl | 3 m | |
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| Number of notional lanes nl | 3 | |
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| Lane 1: uniform load qk1 | 9 kN/m² | |
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| Lane 1: load of one axle of the tandem Qk1 | 300 kN | |
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| Lane 2: uniform load qk2 | 2.5 kN/m² | |
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| Lane 2: load of one axle of the tandem Qk2 | 200 kN | |
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| Lane 3: uniform load qk3 | 2.5 kN/m² | |
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| Lane 3: load of one axle of the tandem Qk3 | 100 kN | |
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| Uniform load on the remaining area qkr | 2.5 kN/m² | |
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| Adjustment factor of the uniform loads αq | 0.9 | |
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| Adjustment factor of the tandems αQ | 0.9 | |
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| Load factor for the permanent loads γG | 1.35 | |
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| Load factor for the road traffic γQ | 1.5 | |
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| Height of the tendons above the bottom face yp,f | 200 mm | |
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| Depth of the tendons below the top face yp,s | 250 mm | |
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| Strands per tendon ns | 19 | |
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| Tendons chosen at mid-span (optional) nt,f | 6 | |
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| Tendons chosen over the supports (optional) nt,s | 10 | |
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Calculation: The bridge| Step | Value | Ref. |
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| Total length2·le + (n − 2)·li | L = 117.00 m | |
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| End span to interior spanabout 0.8: the end spans balance the interior spans | le/li = 0.80 | |
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| Slenderness of the girderbox girders of constant depth commonly lie between about 16 and 25 | l/h = 18.8 | |
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Calculation: Properties of the cross-sections| Step | Value | Ref. |
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| Stiffness over the supportsthe stiffer support zones attract more of the hogging moment | Ic,s/Ic,f = 1.24 | |
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| Inclination of the websfrom the vertical, the same in both sections | βw = 19.5 ° | |
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| Step | 1In the spans | 2Over the supportsls = 8.0 m each side | Ref. |
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| Area Ac m²outline minus the cell | 6.455 | 7.659 | |
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| Height of the centroid yG mmabove the bottom face | 1,559 | 1,410 | |
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| Second moment of area Ic m⁴ | 5.089 | 6.294 | |
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| Section modulus, top Wt m³Ic/(h − yG) | 6.051 | 6.357 | |
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| Section modulus, bottom Wb m³Ic/yG | 3.264 | 4.464 | |
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| Efficiency of the section ρIc/(Ac·yt·yb) | 0.60 | 0.59 | |
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| Self-weight g1 kN/mγ·Ac | 161.4 | 191.5 | |
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Calculation: Permanent loads| Step | Value | Ref. |
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| Self-weight of the girder in the spansγ·Ac,f | g1,f = 161.4 kN/m | |
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| Self-weight over the supportsγ·Ac,sover ls = 8.0 m on each side of every interior support | g1,s = 191.5 kN/m | |
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| Edge beams and parapets | g2,e = 10.0 kN/m | |
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| Safety barriers | g2,b = 2.0 kN/m | |
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| SurfacingBr·er·γr | g2,r = 25.2 kN/m | |
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| Further permanent loadsg2,e + g2,b + g2,r | g2 = 37.2 kN/m | |
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| All permanent loads in the spansg1,f + g2 | gk,f = 198.6 kN/m | |
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| All permanent loads over the supportsg1,s + g2 | gk,s = 228.7 kN/m | |
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Calculation: Road traffic| Step | Value | Ref. |
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| Width of the remaining areaBr − nl·wl | br = 1.50 m | |
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| Uniform traffic load on the girderαq·(Σ qk,i·wl + qkr·br)the whole carriageway loaded, the girder carries the full width | qk = 41.2 kN/m | |
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| All the tandems togetherαQ·Σ 2·Qk,itwo axles 1.2 m apart in each lane, side by side | Qk = 1,080 kN | |
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Calculation: Design loads| Step | Value | Ref. |
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| Uniform design loadγG·gk + γQ·qk | (g + q)d = 329.8 kN/m | |
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| Design load of the tandemsγQ·Qk | Qd = 1,620 kN | |
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Calculation: Design moments of the continuous girder| Step | 1End spanx = 14.3 m | 2Last interior supportx = 81.0 m | 3Interior spanx = 58.5 m | Ref. |
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| Permanent loads, characteristic Mg MNmgk,f on every span, gk,s over ls | 17.1 | -35.5 | 15.8 | |
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| Uniform traffic, characteristic Mq MNmqk on the spans that make it largest | 5.4 | -8.2 | 5.7 | |
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| Tandems, characteristic MQ MNmQk at the worst position | 7.7 | -4.5 | 7.6 | |
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| Design moment Md MNmγG·Mg + γQ·(Mq + MQ) | 42.8 | -66.9 | 41.2 | |
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Calculation: Quick estimate: an interior span fixed at both ends| Step | Value | Ref. |
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| Largest sagging moment(g + q)d·li²/24 + Qd·li/8continuous analysis: 41.2 MNm | Md,f = 36.9 MNm | |
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| Hogging moment at the supports−(g + q)d·li²/12 − Qd·li/8continuous analysis: -66.9 MNm | Md,s = -64.8 MNm | |
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Calculation: Quick estimate of the prestressing steel| Step | Value | Ref. |
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| Design strength of the prestressing steelfp0,1k/γs | fpd = 1,304.3 N/mm² | § 2.4.2.5 (5) |
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| Step | 1End spanx = 14.3 m | 2Last interior supportx = 81.0 m | 3Interior spanx = 58.5 m | Ref. |
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| Permanent loads, characteristic |Mg,k| MNmfrom the table above | 17.1 | 35.5 | 15.8 | |
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| Lever arm, first estimate z mm0.8·h | 1,920 | 1,920 | 1,920 | |
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| Prestressing steel, first estimate Ap,est mm²|Mg,k|/(z·fpd) | 6,836 | 14,159 | 6,297 | |
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| Strands, first estimate nestAp,est/Ap1 | 45.6 | 94.4 | 42.0 | |
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Calculation: Design strengths| Step | Value | Ref. |
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| Concreteηfc·ηt·fck/γcηfc = (40/fck)^(1/3) ≤ 1 (26) | fcd = 26.67 N/mm² | § 2.4.2.3 (2) |
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| Reinforcing steelfyk/γs | fsd = 434.8 N/mm² | § 2.4.2.5 (4) |
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| Prestressing steelfp0,1k/γs | fpd = 1,304.3 N/mm² | § 2.4.2.5 (5) |
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Calculation: Effective widths of the compressed slabs| Step | Value | Ref. |
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| End span: top slab2·(bw + beff,out + beff,in) ≤ Bl0 = 30.60 m (4.1.3.3.3); cantilever 3,000, inside 2,800 mm each side of a web; span section | beff,t = 12,500 mm | § 4.1.3.3.2 (19), (20) |
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| Last interior support: bottom slab2·(bw + beff,i), beff,i = 0.2·bi + 0.1·l0 ≤ 0.2·l0 ≤ bil0 = 12.15 m (4.1.3.3.3), bi = 2,109 mm half the slab between the webs; support section | beff,b = 4,374 mm | § 4.1.3.3.2 (19), (20) |
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| Interior span: top slab2·(bw + beff,out + beff,in) ≤ Bl0 = 31.50 m (4.1.3.3.3); cantilever 3,000, inside 2,800 mm each side of a web; span section | beff,t = 12,500 mm | § 4.1.3.3.2 (19), (20) |
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Calculation: Check 1 — prestress at mid-span: end span, x = 14.3 m| Step | Value | Ref. |
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| Design momentsagging, span section: tt = 280, bw = 450 mm | Md = 42.8 MNm | |
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| Effective depth of the tendonsh − yp,f | dp = 2,200 mm | |
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| Lever arm of the tendonsdp − depth of the compression resultantcompression within the top slab | zp = 2,170 mm | |
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| Prestressing steel needed(Md − As·fsd·zs)/(fpd·zp) | Ap,req = 15,101 mm² | § 4.1.5.5.1 |
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| Strands neededAp,req/Ap1 | nreq = 100.7 | |
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| Tendons needed2·⌈nreq/(2·ns)⌉of 19 strands, half in each web | nt,req = 6 | |
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| Prestressing steel chosennt·ns·Ap1 | Ap = 17,100 mm² | |
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| Lever arm with the steel chosenthe compression block of Ap·fpdcompression within the top slab | zp = 2,167 mm | |
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| Resistance of the coupleAp·fpd·zp + As·fsd·zs | MRd = 48.3 MNm | |
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| Design moment against the resistance of the coupleMd/MRd | η = 0.885 · Pass88 % of the capacity used | § 4.1.5.5.1 |
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| Depth of the compression zonea/0.85, a the depth of the blockslab 280 mm thick | x = 79 mm | |
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| Compression zone shallow enough for a ductile section(x/dp)/(0.5·435/fyd) | η = 0.072 · Pass7 % of the capacity used | § 4.1.4.2.6 |
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Calculation: Check 2 — prestress over the support: last interior support, x = 81.0 m| Step | Value | Ref. |
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| Design momenthogging, support section: tb,s = 450, bw,s = 550 mm | Md = -66.9 MNm | |
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| Effective depth of the tendonsh − yp,s | dp = 2,150 mm | |
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| Lever arm of the tendonsdp − depth of the compression resultantcompression within the bottom slab | zp = 2,007 mm | |
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| Prestressing steel needed(Md − As·fsd·zs)/(fpd·zp) | Ap,req = 25,565 mm² | § 4.1.5.5.1 |
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| Strands neededAp,req/Ap1 | nreq = 170.4 | |
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| Tendons needed2·⌈nreq/(2·ns)⌉of 19 strands, half in each web | nt,req = 10 | |
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| Prestressing steel chosennt·ns·Ap1 | Ap = 28,500 mm² | |
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| Lever arm with the steel chosenthe compression block of Ap·fpdcompression within the bottom slab | zp = 1,991 mm | |
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| Resistance of the coupleAp·fpd·zp + As·fsd·zs | MRd = 74.0 MNm | |
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| Design moment against the resistance of the coupleMd/MRd | η = 0.904 · Pass90 % of the capacity used | § 4.1.5.5.1 |
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| Depth of the compression zonea/0.85, a the depth of the blockslab 450 mm thick | x = 375 mm | |
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| Compression zone shallow enough for a ductile section(x/dp)/(0.5·435/fyd) | η = 0.349 · Pass35 % of the capacity used | § 4.1.4.2.6 |
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Calculation: Check 3 — prestress at mid-span: interior span, x = 58.5 m| Step | Value | Ref. |
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| Design momentsagging, span section: tt = 280, bw = 450 mm | Md = 41.2 MNm | |
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| Effective depth of the tendonsh − yp,f | dp = 2,200 mm | |
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| Lever arm of the tendonsdp − depth of the compression resultantcompression within the top slab | zp = 2,172 mm | |
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| Prestressing steel needed(Md − As·fsd·zs)/(fpd·zp) | Ap,req = 14,556 mm² | § 4.1.5.5.1 |
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| Strands neededAp,req/Ap1 | nreq = 97.0 | |
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| Tendons needed2·⌈nreq/(2·ns)⌉of 19 strands, half in each web | nt,req = 6 | |
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| Prestressing steel chosennt·ns·Ap1 | Ap = 17,100 mm² | |
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| Lever arm with the steel chosenthe compression block of Ap·fpdcompression within the top slab | zp = 2,167 mm | |
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| Resistance of the coupleAp·fpd·zp + As·fsd·zs | MRd = 48.3 MNm | |
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| Design moment against the resistance of the coupleMd/MRd | η = 0.853 · Pass85 % of the capacity used | § 4.1.5.5.1 |
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| Depth of the compression zonea/0.85, a the depth of the blockslab 280 mm thick | x = 79 mm | |
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| Compression zone shallow enough for a ductile section(x/dp)/(0.5·435/fyd) | η = 0.072 · Pass7 % of the capacity used | § 4.1.4.2.6 |
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How this module is verified
Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.
Questions
Why an end span of about 0.8 times an interior span?
Under a uniform load, this ratio makes the support moments of the end spans about equal to those of the interior spans.
Can I design with the fixed-ended span?
No. It ignores the rotation of the supports under unsymmetrical traffic and underestimates the sagging moment of an interior span. In the worked example it gives 36.9 MNm against 41.2 MNm from the continuous analysis, which governs.
Can I print the calculation?
The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.
Related
Norm: SIA 262:2025 · Page updated: 8 November 2026