Box-girder bridge, longitudinal predimensioning to SIA 262

The code governs which inputs appear and how every value is derived.

Member

Material properties, shared by every verification. The cross-section is not shared: SIA 262 works from the section as sized for each internal-force case, so it belongs to each verification and appears with it.

About this check

clauses, worked example and questions

Sizes a continuous box girder of constant depth to SIA 262:2025, with one cross-section or a thicker one over the supports: the section properties, the actions with load model 1 of SIA 261, the design moments of the continuous girder and the first prestress by the force couple. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You enter the number of spans, le and li, the outline of the box (B, h, bc, binf) with the thicknesses tt, bw and tb in the spans, and optionally thicker ones over the interior supports over a length ls. Then the materials and resistance factors, the edge beams, barriers and surfacing, the lanes of load model 1, γG and γQ. For the prestress: the height of the tendons at mid-span and over the supports, optional bars in the tension chord, the strands per tendon and the tendons chosen.

You get the loads, the moments along the girder, the tendons needed and the resistance of the couple at each key section, with the utilisation of each check and a pass or fail.

Assumptions and limits

Worked example

Three spans of 36, 45 and 36 m, a deck 12.5 m wide and a girder 2,400 mm deep, thicker over 8 m on each side of the interior supports, fck = 40 N/mm², three notional lanes of 3 m, and tendons of 19 strands: 6 at mid-span and 10 over the supports. Every check passes. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Number of spans n3
Span lengthsEnd spans alike, interior spans alike
End spans le36 m
Interior spans li45 m
Cross-section along the bridgeA thicker section over the interior supports
Width of the deck B12.5 m
Depth of the girder h2400 mm
Thickness of the top slab tt280 mm
Length of each cantilever bc3.0 m
Thickness of a web bw450 mm
Width of the bottom slab binf5.0 m
Thickness of the bottom slab tb250 mm
Thickness of the top slab tt,s280 mm
Thickness of a web bw,s550 mm
Thickness of the bottom slab tb,s450 mm
Length of this section on each side of a support ls8 m
Characteristic compressive strength fck40 N/mm²
Unit weight of the reinforced concrete γ25 kN/m³
Yield strength of the reinforcing steel fyk500 N/mm²
Proof stress of the prestressing steel fp0,1k1500 N/mm²
Area of one strand Ap1150 mm²
Resistance factor for concrete γc1.5§ 2.4.2.6
Resistance factor for steel γs1.15§ 2.4.2.6
Duration factor ηt1.0 — both conditions of 4.2.1.3 met§ 4.2.1.3
Edge beams and parapets, both sides g2,e10 kN/m
Safety barriers, both sides g2,b2 kN/m
Width of the surfacing Br10.5 m
Thickness of the surfacing er100 mm
Unit weight of the surfacing γr24 kN/m³
Width of a notional lane wl3 m
Number of notional lanes nl3
Lane 1: uniform load qk19 kN/m²
Lane 1: load of one axle of the tandem Qk1300 kN
Lane 2: uniform load qk22.5 kN/m²
Lane 2: load of one axle of the tandem Qk2200 kN
Lane 3: uniform load qk32.5 kN/m²
Lane 3: load of one axle of the tandem Qk3100 kN
Uniform load on the remaining area qkr2.5 kN/m²
Adjustment factor of the uniform loads αq0.9
Adjustment factor of the tandems αQ0.9
Load factor for the permanent loads γG1.35
Load factor for the road traffic γQ1.5
Height of the tendons above the bottom face yp,f200 mm
Depth of the tendons below the top face yp,s250 mm
Strands per tendon ns19
Tendons chosen at mid-span (optional) nt,f6
Tendons chosen over the supports (optional) nt,s10
Calculation: The bridge
StepValueRef.
Total length2·le + (n − 2)·liL = 117.00 m
End span to interior spanabout 0.8: the end spans balance the interior spansle/li = 0.80
Slenderness of the girderbox girders of constant depth commonly lie between about 16 and 25l/h = 18.8
Calculation: Properties of the cross-sections
StepValueRef.
Stiffness over the supportsthe stiffer support zones attract more of the hogging momentIc,s/Ic,f = 1.24
Inclination of the websfrom the vertical, the same in both sectionsβw = 19.5 °
Step1In the spans2Over the supportsls = 8.0 m each sideRef.
Area Ac m²outline minus the cell6.4557.659
Height of the centroid yG mmabove the bottom face1,5591,410
Second moment of area Ic m⁴5.0896.294
Section modulus, top Wt m³Ic/(h − yG)6.0516.357
Section modulus, bottom Wb m³Ic/yG3.2644.464
Efficiency of the section ρIc/(Ac·yt·yb)0.600.59
Self-weight g1 kN/mγ·Ac161.4191.5
Calculation: Permanent loads
StepValueRef.
Self-weight of the girder in the spansγ·Ac,fg1,f = 161.4 kN/m
Self-weight over the supportsγ·Ac,sover ls = 8.0 m on each side of every interior supportg1,s = 191.5 kN/m
Edge beams and parapetsg2,e = 10.0 kN/m
Safety barriersg2,b = 2.0 kN/m
SurfacingBr·er·γrg2,r = 25.2 kN/m
Further permanent loadsg2,e + g2,b + g2,rg2 = 37.2 kN/m
All permanent loads in the spansg1,f + g2gk,f = 198.6 kN/m
All permanent loads over the supportsg1,s + g2gk,s = 228.7 kN/m
Calculation: Road traffic
StepValueRef.
Width of the remaining areaBr − nl·wlbr = 1.50 m
Uniform traffic load on the girderαq·(Σ qk,i·wl + qkr·br)the whole carriageway loaded, the girder carries the full widthqk = 41.2 kN/m
All the tandems togetherαQ·Σ 2·Qk,itwo axles 1.2 m apart in each lane, side by sideQk = 1,080 kN
Calculation: Design loads
StepValueRef.
Uniform design loadγG·gk + γQ·qk(g + q)d = 329.8 kN/m
Design load of the tandemsγQ·QkQd = 1,620 kN
Calculation: Design moments of the continuous girder
Step1End spanx = 14.3 m2Last interior supportx = 81.0 m3Interior spanx = 58.5 mRef.
Permanent loads, characteristic Mg MNmgk,f on every span, gk,s over ls17.1-35.515.8
Uniform traffic, characteristic Mq MNmqk on the spans that make it largest5.4-8.25.7
Tandems, characteristic MQ MNmQk at the worst position7.7-4.57.6
Design moment Md MNmγG·Mg + γQ·(Mq + MQ)42.8-66.941.2
Calculation: Quick estimate: an interior span fixed at both ends
StepValueRef.
Largest sagging moment(g + q)d·li²/24 + Qd·li/8continuous analysis: 41.2 MNmMd,f = 36.9 MNm
Hogging moment at the supports−(g + q)d·li²/12 − Qd·li/8continuous analysis: -66.9 MNmMd,s = -64.8 MNm
Calculation: Quick estimate of the prestressing steel
StepValueRef.
Design strength of the prestressing steelfp0,1k/γsfpd = 1,304.3 N/mm²§ 2.4.2.5 (5)
Step1End spanx = 14.3 m2Last interior supportx = 81.0 m3Interior spanx = 58.5 mRef.
Permanent loads, characteristic |Mg,k| MNmfrom the table above17.135.515.8
Lever arm, first estimate z mm0.8·h1,9201,9201,920
Prestressing steel, first estimate Ap,est mm²|Mg,k|/(z·fpd)6,83614,1596,297
Strands, first estimate nestAp,est/Ap145.694.442.0
Calculation: Design strengths
StepValueRef.
Concreteηfc·ηt·fck/γcηfc = (40/fck)^(1/3) ≤ 1 (26)fcd = 26.67 N/mm²§ 2.4.2.3 (2)
Reinforcing steelfyk/γsfsd = 434.8 N/mm²§ 2.4.2.5 (4)
Prestressing steelfp0,1k/γsfpd = 1,304.3 N/mm²§ 2.4.2.5 (5)
Calculation: Effective widths of the compressed slabs
StepValueRef.
End span: top slab2·(bw + beff,out + beff,in) ≤ Bl0 = 30.60 m (4.1.3.3.3); cantilever 3,000, inside 2,800 mm each side of a web; span sectionbeff,t = 12,500 mm§ 4.1.3.3.2 (19), (20)
Last interior support: bottom slab2·(bw + beff,i), beff,i = 0.2·bi + 0.1·l0 ≤ 0.2·l0 ≤ bil0 = 12.15 m (4.1.3.3.3), bi = 2,109 mm half the slab between the webs; support sectionbeff,b = 4,374 mm§ 4.1.3.3.2 (19), (20)
Interior span: top slab2·(bw + beff,out + beff,in) ≤ Bl0 = 31.50 m (4.1.3.3.3); cantilever 3,000, inside 2,800 mm each side of a web; span sectionbeff,t = 12,500 mm§ 4.1.3.3.2 (19), (20)
Calculation: Check 1 — prestress at mid-span: end span, x = 14.3 m
StepValueRef.
Design momentsagging, span section: tt = 280, bw = 450 mmMd = 42.8 MNm
Effective depth of the tendonsh − yp,fdp = 2,200 mm
Lever arm of the tendonsdp − depth of the compression resultantcompression within the top slabzp = 2,170 mm
Prestressing steel needed(Md − As·fsd·zs)/(fpd·zp)Ap,req = 15,101 mm²§ 4.1.5.5.1
Strands neededAp,req/Ap1nreq = 100.7
Tendons needed2·⌈nreq/(2·ns)⌉of 19 strands, half in each webnt,req = 6
Prestressing steel chosennt·ns·Ap1Ap = 17,100 mm²
Lever arm with the steel chosenthe compression block of Ap·fpdcompression within the top slabzp = 2,167 mm
Resistance of the coupleAp·fpd·zp + As·fsd·zsMRd = 48.3 MNm
Design moment against the resistance of the coupleMd/MRdη = 0.885 · Pass88 % of the capacity used§ 4.1.5.5.1
Depth of the compression zonea/0.85, a the depth of the blockslab 280 mm thickx = 79 mm
Compression zone shallow enough for a ductile section(x/dp)/(0.5·435/fyd)η = 0.072 · Pass7 % of the capacity used§ 4.1.4.2.6
Calculation: Check 2 — prestress over the support: last interior support, x = 81.0 m
StepValueRef.
Design momenthogging, support section: tb,s = 450, bw,s = 550 mmMd = -66.9 MNm
Effective depth of the tendonsh − yp,sdp = 2,150 mm
Lever arm of the tendonsdp − depth of the compression resultantcompression within the bottom slabzp = 2,007 mm
Prestressing steel needed(Md − As·fsd·zs)/(fpd·zp)Ap,req = 25,565 mm²§ 4.1.5.5.1
Strands neededAp,req/Ap1nreq = 170.4
Tendons needed2·⌈nreq/(2·ns)⌉of 19 strands, half in each webnt,req = 10
Prestressing steel chosennt·ns·Ap1Ap = 28,500 mm²
Lever arm with the steel chosenthe compression block of Ap·fpdcompression within the bottom slabzp = 1,991 mm
Resistance of the coupleAp·fpd·zp + As·fsd·zsMRd = 74.0 MNm
Design moment against the resistance of the coupleMd/MRdη = 0.904 · Pass90 % of the capacity used§ 4.1.5.5.1
Depth of the compression zonea/0.85, a the depth of the blockslab 450 mm thickx = 375 mm
Compression zone shallow enough for a ductile section(x/dp)/(0.5·435/fyd)η = 0.349 · Pass35 % of the capacity used§ 4.1.4.2.6
Calculation: Check 3 — prestress at mid-span: interior span, x = 58.5 m
StepValueRef.
Design momentsagging, span section: tt = 280, bw = 450 mmMd = 41.2 MNm
Effective depth of the tendonsh − yp,fdp = 2,200 mm
Lever arm of the tendonsdp − depth of the compression resultantcompression within the top slabzp = 2,172 mm
Prestressing steel needed(Md − As·fsd·zs)/(fpd·zp)Ap,req = 14,556 mm²§ 4.1.5.5.1
Strands neededAp,req/Ap1nreq = 97.0
Tendons needed2·⌈nreq/(2·ns)⌉of 19 strands, half in each webnt,req = 6
Prestressing steel chosennt·ns·Ap1Ap = 17,100 mm²
Lever arm with the steel chosenthe compression block of Ap·fpdcompression within the top slabzp = 2,167 mm
Resistance of the coupleAp·fpd·zp + As·fsd·zsMRd = 48.3 MNm
Design moment against the resistance of the coupleMd/MRdη = 0.853 · Pass85 % of the capacity used§ 4.1.5.5.1
Depth of the compression zonea/0.85, a the depth of the blockslab 280 mm thickx = 79 mm
Compression zone shallow enough for a ductile section(x/dp)/(0.5·435/fyd)η = 0.072 · Pass7 % of the capacity used§ 4.1.4.2.6

How this module is verified

Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.

Questions

Why an end span of about 0.8 times an interior span?

Under a uniform load, this ratio makes the support moments of the end spans about equal to those of the interior spans.

Can I design with the fixed-ended span?

No. It ignores the rotation of the supports under unsymmetrical traffic and underestimates the sagging moment of an interior span. In the worked example it gives 36.9 MNm against 41.2 MNm from the continuous analysis, which governs.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 262:2025 · Page updated: 8 November 2026