Structural Engineering Tools

Bolted beam splice with flange and web cover plates to SIA 263

Checks a rolled beam spliced with bolted flange and web cover plates under a bending moment and a shear force, to SIA 263:2013: the split of the moment, then the flange joint and the web joint. Every step shows its formula and the clause it comes from.

Pro SIA 263:2013

Part of the Pro plan

This module is included in the Pro plan and above, with its calculation note.

About this check

clauses, worked example and questions

Checks a rolled beam spliced with bolted flange and web cover plates under a bending moment and a shear force, to SIA 263:2013: the split of the moment, then the flange joint and the web joint. Every step shows its formula and the clause it comes from.

What it checks

  • The bolts: one shear plane resists Fv,Rd = 0.6 · fub,k · A/γM2, equation (75), with the hole d0 of table 17.
  • Split of the moment, MEd = Mw + Mf: the flange plates alone, an elastic split by the inertias Iw = nw · tp · hp³/12 and If = 2 · Af · (a/2)², or a plastic split by Wpl,w = nw · tp · hp²/4 and Wpl,f = Af · a, with a = h − tf.
  • Flange joint: Nf = Mf/a, shared by nf = n1,f · n2,f bolts with two shear planes. Bearing, equation (76): 0.85 · (e/d0) · fu,k · d · t/γM2 ≤ 2.4 · fu,k · d · t/γM2, on the beam flange under the whole bolt force and on the outer and inner plates under half of it each.
  • Flange plates and beam flange: the gross section fy,k · Af/γM1, equation (38), and the net sections 0.9 · fu,k · Anet/γM2, clause 5.1.2.2 and equation (39), on the tension side.
  • Web joint: the shear acts with the eccentricity e = g/2 + ex,b + (nc − 1) · p2,w/2 from the hinge at mid-gap. The group carries VEd/n and Me + Mw elastically; the most loaded bolt takes FEd = √(Fx² + Fz²).
  • Web plates and beam web: bearing, equation (76); the gross shear Av · fy,k/(√3 · γM1), equation (41); the net shear 0.9 · fu,k · Av,net/(√3 · γM2), equation (82), the beam web taking Av from equation (42a) less the holes (clause 5.1.4.3).
  • Placing of the holes, flanges and web: e1, e2, p1 and p2 against the minimum of table 17, with e2 ≥ d0 and p2 ≥ 2 · d0 for the bearing resistance.

What you enter and what you get

You enter fy,k and fu,k from table 1, the five dimensions of the rolled profile, the bolt grade (table 2) and size, whether the shear planes cross the shank or the thread, γM1 and γM2 (clause 4.1.3), MEd, VEd and the gap g. For the flanges: the cover plates (outer and two inner plates, outer plate only, or none), the split of the moment, the plate sizes and the bolt rows, lines, gauge and end distances. For the web: one or two plates, tp, hp and the bolt columns and rows.

You get every force and resistance and the utilisation of each check with a pass or fail. With the Pro plan, it prints as an A4 calculation note.

Assumptions and limits

  • A normal force is not included.
  • Without flange plates the flanges are not spliced and the web plates carry the whole moment.
  • The two shear planes of a flange bolt are taken as equally loaded.
  • In compression the holes are filled and the gross section governs.
  • The inner plates fit beside the web, at most (b − tw)/2 − r wide; the web plates fit between the root fillets.

Worked example

A rolled beam with h = 390 mm, b = 300 mm, tw = 11 mm, tf = 19 mm and r = 27 mm in fy,k = 235 N/mm², under MEd = 250 kN·m and VEd = 200 kN, spliced with M20 bolts of grade 4.6 sheared in the shank: an outer plate of 300 × 8 mm and two inner plates of 90 × 10 mm carrying the whole moment with three rows at 70 mm and two lines on each side, and two web plates of 4 × 280 mm with two columns and two rows. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Characteristic yield strength fy,k235 N/mm²§ t.1
Characteristic tensile strength fu,k360 N/mm²§ t.1
Overall depth h390 mm
Flange width b300 mm
Web thickness tw11 mm
Flange thickness tf19 mm
Root radius r27 mm
Bolt grade4.6§ t.2
Bolt sizeM20§ t.17
The shear planes cross theShank — the unthreaded part
Resistance factor, gross sections γM11.05§ 4.1.3
Resistance factor, bolts, welds and net sections γM21.25§ 4.1.3
Design bending moment at the splice MEd250 kN·m
Design shear force at the splice VEd200 kN
Gap between the two beam ends g10 mm
Flange cover platesOuter plate and two inner plates — two shear planes
Split of the bending momentFlanges alone carry the moment
Outer plate, width bo300 mm
Outer plate, thickness to8 mm
Inner plates, width of one bi90 mm
Inner plates, thickness ti10 mm
Rows along the beam n1,f3
Pitch along the beam p1,f70 mm
Lines across the flange n2,f2
Gauge between the two lines nearest the web w160 mm
End distance in the beam flange e1,b40 mm
End distance in the flange plates e1,p40 mm
Web cover platesTwo plates, one on each face — two shear planes
Thickness of one plate tp4 mm
Depth of the plates hp280 mm
Columns nc2
Horizontal pitch p2,w60 mm
Rows nr2
Vertical pitch p1,w200 mm
Beam end to the first column ex,b40 mm
Outer column to the plate end ex,p40 mm
Calculation: Common values
StepValueRef.
Bolt– = M20, grade 4.6, hole d0 = 22 mm§ t.17
Shear resistance of one plane0,6·fub,k·A/γM2, fub,k = 400 N/mm², A = 314.2 mm².Fv,Rd = 60.32 kN§ (75)
Lever of the flange forcesa = h − tf, between the flange centroids.a = 371.0 mm
Inertia of the web platesnw·tp·hp³/12.Iw = 14.635 10⁶ mm⁴
Inertia of the flange plates2·Af·(a/2)², their own inertia neglected.If = 289.046 10⁶ mm⁴
Plastic modulus of the web platesnw·tp·hp²/4.Wpl,w = 156,800 mm³
Plastic modulus of the flange platesAf·a.Wpl,f = 1,558,200 mm³
Share of the moment on the web platesThe flange plates carry the whole moment; the web plates the shear alone.Mw/MEd = 0.0000
Moment on the flange platesMf = MEd − Mw.Mf = 250.00 kN·m
Flange forceNf = Mf/a: tension in one flange, compression in the other.Nf = 673.9 kN
Area of the flange plates at one flangebo·to + 2·bi·ti = 2,400 + 1,800.Af = 4,200 mm²
Flange bolts on each siden1,f·n2,f = 3·2.nf = 6
Force on one shear planeNf/(nf·2): the outer plate and the inner plates each take one plane, equally loaded when Ao = Ai.Fv,Ed = 56.15 kN
Calculation: Check 1 — flange bolts in shear
StepValueRef.
Flange bolts in shearFv,Ed ≤ Fv,Rdη = 0.931 · Pass93 % of the capacity used§ (75)
Calculation: Check 2 — bearing on the beam flange
StepValueRef.
End distance usede1,b, from the beam end.e = 40.0 mm§ (76)
Bearing resistance per bolt0,85·(e/d0)·fu,k·d·t/γM2 ≤ 2,4·fu,k·d·t/γM2, t = 19.0 mm.Fb,Rd = 169.13 kN§ (76)
Bearing on the beam flangeFb,Ed ≤ Fb,Rdη = 0.664 · Pass66 % of the capacity used§ (76)
Calculation: Check 3 — bearing on the outer plate
StepValueRef.
End distance usede1,p, from the plate end.e = 40.0 mm§ (76)
Bearing resistance per bolt0,85·(e/d0)·fu,k·d·t/γM2 ≤ 2,4·fu,k·d·t/γM2, t = 8.0 mm.Fb,Rd = 71.21 kN§ (76)
Bearing on the outer plateFb,Ed ≤ Fb,Rdη = 0.789 · Pass79 % of the capacity used§ (76)
Calculation: Check 4 — bearing on an inner plate
StepValueRef.
End distance usede1,p, from the plate end.e = 40.0 mm§ (76)
Bearing resistance per bolt0,85·(e/d0)·fu,k·d·t/γM2 ≤ 2,4·fu,k·d·t/γM2, t = 10.0 mm.Fb,Rd = 89.02 kN§ (76)
Bearing on an inner plateFb,Ed ≤ Fb,Rdη = 0.631 · Pass63 % of the capacity used§ (76)
Calculation: Check 5 — flange plates, gross section
StepValueRef.
Resistance of the gross sectionfy,k·Af/γM1.NRd = 940.0 kN§ (38)
Flange plates, gross sectionNf ≤ NRdη = 0.717 · Pass72 % of the capacity used§ (38)
Calculation: Check 6 — flange plates, net section
StepValueRef.
Net areaAf less 2 holes in the outer plate and 1 in each inner plate.Anet = 3,408 mm²§ 5.1.2.2
Resistance of the net section0,9·fu,k·Anet/γM2.Nu,Rd = 883.4 kN§ (39)
Flange plates, net sectionNf ≤ Nu,Rdη = 0.763 · Pass76 % of the capacity used§ (39)
Calculation: Check 7 — beam flange, net section
StepValueRef.
Net area of the beam flange(b − n2,f·d0)·tf.Anet = 4,864 mm²§ 5.1.2.2
Resistance0,9·fu,k·Anet/γM2.Nu,Rd = 1,260.7 kN§ (39)
Beam flange, net sectionNf ≤ Nu,Rdη = 0.534 · Pass53 % of the capacity used§ (39)
Calculation: Check 8 — end distance
StepValueRef.
End distancee1 ≥ 30 mmη = 0.750 · Pass75 % of the capacity used§ t.17
Calculation: Check 9 — edge distance
StepValueRef.
Edge distancee2 ≥ 25 mmη = 0.588 · Pass59 % of the capacity used§ t.17
Calculation: Check 10 — pitch in the direction of the force
StepValueRef.
Pitch in the direction of the forcep1 ≥ 45 mmη = 0.643 · Pass64 % of the capacity used§ t.17
Calculation: Check 11 — spacing across the force
StepValueRef.
Spacing across the forcep2 ≥ 45 mmη = 0.281 · Pass28 % of the capacity used§ t.17
Calculation: Common values
StepValueRef.
Bolt– = M20, grade 4.6, hole d0 = 22 mm§ t.17
Shear resistance of one plane0,6·fub,k·A/γM2, fub,k = 400 N/mm², A = 314.2 mm².Fv,Rd = 60.32 kN§ (75)
Eccentricity of the sheare = g/2 + ex,b + (nc − 1)·p2,w/2 = 5.0 + 40 + 30.0: from the hinge at mid-gap to the centroid of the bolts on one side.e = 75.0 mm
Eccentricity momentMe = VEd·e. It remains whatever the split of the moment.Me = 15.000 kN·m
Moment on the web platesFrom the split of the moment.Mw = 0.00 kN·m§ (9.8)
Bolts on each sidenc·nr = 2·2.n = 4
Polar second moment of the groupΣ(x² + z²) = 43,600 mm²
Horizontal force on the worst bolt(Me + Mw)·z/Σ(x² + z²), at z = 100 mm.Fx = 34.40 kN
Vertical force on the worst boltVEd/n + (Me + Mw)·x/Σ(x² + z²), at x = 30 mm.Fz = 60.32 kN
Force on the most loaded bolt√(Fx² + Fz²).FEd = 69.44 kN
Force on one shear planeFEd/2: two web plates, two shear planes.Fv,Ed = 34.72 kN
Calculation: Check 1 — web bolts in shear
StepValueRef.
Web bolts in shearFv,Ed ≤ Fv,Rdη = 0.576 · Pass58 % of the capacity used§ (75)
Calculation: Check 2 — bearing on one web plate
StepValueRef.
End distance usedThe smaller of the vertical edge distance 40.0 mm and ex,p: the bolt force is inclined, so both edges are taken.e = 40.0 mm§ (76)
Bearing resistance per bolt0,85·(e/d0)·fu,k·d·t/γM2 ≤ 2,4·fu,k·d·t/γM2, t = 4.0 mm.Fb,Rd = 35.61 kN§ (76)
Bearing on one web plateFb,Ed ≤ Fb,Rdη = 0.975 · Pass98 % of the capacity used§ (76)
Calculation: Check 3 — bearing on the beam web
StepValueRef.
End distance usedex,b, from the beam end.e = 40.0 mm§ (76)
Bearing resistance per bolt0,85·(e/d0)·fu,k·d·t/γM2 ≤ 2,4·fu,k·d·t/γM2, t = 11.0 mm.Fb,Rd = 97.92 kN§ (76)
Bearing on the beam webFb,Ed ≤ Fb,Rdη = 0.709 · Pass71 % of the capacity used§ (76)
Calculation: Check 4 — web plates, gross section in shear
StepValueRef.
Gross shear areanw·tp·hp.Av = 2,240 mm²
Shear resistanceAv·fy,k/(√3·γM1).VRd = 289.4 kN§ (41)
Web plates, gross section in shearVEd ≤ VRdη = 0.691 · Pass69 % of the capacity used§ (41)
Calculation: Check 5 — web plates, net section in shear
StepValueRef.
Net shear areanw·(hp − nr·d0)·tp, along a column of holes.Av,net = 1,888 mm²§ (82)
Resistance0,9·fu,k·Av,net/(√3·γM2).Veff,Rd = 282.5 kN§ (82)
Web plates, net section in shearVEd ≤ Veff,Rdη = 0.708 · Pass71 % of the capacity used§ (82)
Calculation: Check 6 — beam web, net section in shear
StepValueRef.
Shear area of the beamA − 2b·tf + (tw + 2r)·tf.Av = 5,733 mm²§ (42a)
Net shear areaAv − nr·d0·tw.Av,net = 5,249 mm²§ 5.1.4.3
Resistance0,9·fu,k·Av,net/(√3·γM2).Veff,Rd = 785.5 kN§ (82)
Beam web, net section in shearVEd ≤ Veff,Rdη = 0.255 · Pass25 % of the capacity used§ (82)
Calculation: Check 7 — end distance
StepValueRef.
End distancee1 ≥ 30 mmη = 0.750 · Pass75 % of the capacity used§ t.17
Calculation: Check 8 — edge distance
StepValueRef.
Edge distancee2 ≥ 25 mmη = 0.625 · Pass63 % of the capacity used§ t.17
Calculation: Check 9 — pitch in the direction of the force
StepValueRef.
Pitch in the direction of the forcep1 ≥ 45 mmη = 0.225 · Pass23 % of the capacity used§ t.17
Calculation: Check 10 — spacing across the force
StepValueRef.
Spacing across the forcep2 ≥ 45 mmη = 0.750 · Pass75 % of the capacity used§ t.17

How this module is verified

Verified clause by clause against SIA 263:2013 and against independent calculations used on real projects, before release.

Questions

Why are the web bolts loaded by a moment when the flanges carry it all?

The shear reaches each bolt group from the hinge at mid-gap: in the worked example e = 75 mm and Me = 15 kN·m, whatever the split. The most loaded web bolt takes 69.4 kN, 34.7 kN on each shear plane.

Are the two shear planes of a flange bolt really equal?

Only when the outer plate and the inner plates have the same area. In the worked example they have 2,400 and 1,800 mm², and the module warns that the equal split is an approximation.

Which plan includes this module?

The Pro plan, with its calculation note.

Related

Norm: SIA 263:2013 · Page updated: 8 November 2026