Strip footing under a wall to SIA 262

The code governs which inputs appear and how every value is derived.

Member

Material properties, shared by every verification. The cross-section is not shared: SIA 262 works from the section as sized for each internal-force case, so it belongs to each verification and appears with it.

About this check

clauses, worked example and questions

Checks a long concrete footing under a wall, per metre of length, to SIA 262:2025 and SIA 267:2013: the soil with lift-off, the bending, shear and anchorage of the transverse bars, and in service the eccentricity, the settlement, the tilt and the bar stresses. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You enter, per metre of length, the footing width B and thickness h, the wall thickness tw and its offset ew, the backfill Ds, and whether the footing is reinforced or of plain concrete. For a reinforced footing: the cover c, the outer layer, the transverse bars Øt at st, the longitudinal bars Øl at sl, and any top bars. Then the materials, the weights, the resistance factors and ηt. For the ultimate state: nd, md, hd, γG, the pressure distribution, qR,d, and for overturning and sliding nd,inf, γG,inf, φ′k, the base roughness, γφ and γR. Then the anchorage model and the bar ends. In service: the actions of the wall, the load case, σadm, up to three soil layers with t1, ME,1 and γe,1, the length L, sadm, θadm and the crack requirements.

You get every check with its utilisation and clause, the soil pressures and the settlement of the rigid footing. With the Basic plan, it prints as an A4 calculation note.

Assumptions and limits

Worked example

A footing 1.6 m wide and 450 mm thick under a centred 250 mm wall, with 0.6 m of backfill, Ø14 at 150 mm transverse and Ø10 at 200 mm longitudinal bars, fck = 30 N/mm², nd = 380 kN/m, md = 20 kNm/m, hd = 15 kN/m, qR,d = 420 kN/m², nd,inf = 260 kN/m, φ′k = 30°, and in service 270 kN/m and 10 kNm/m on one soil layer with ME,1 = 30 MN/m². These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Width of the footing B1.6 m
Thickness of the footing h450 mm
Thickness of the wall tw0.25 m
Soil cover above the footing Ds0.6 m
FootingReinforced
Cover to the bottom bars c50 mm§ 5.2.2
Outer (lowest) layerTransverse bars
Transverse bars, diameter Øt14 mm
Transverse bars, spacing st150 mm
Longitudinal bars, diameter Øl10 mm
Longitudinal bars, spacing sl200 mm
Top barsNone
Characteristic compressive strength fck30 N/mm²§ 3.1.2.2.2
Mean tensile strength fctm2.9 N/mm²§ 3.1.2.2.4
Modulus of elasticity Ecm33600 N/mm²§ 3.1.2.3.3
Largest aggregate size Dmax32 mm§ 4.3.3.2.1
Characteristic yield strength fyk500 N/mm²§ 3.2.2.2
Modulus of elasticity Es205000 N/mm²§ 3.2.2.4
Unit weight of the concrete γRC25 kN/m³
Unit weight of the backfill γe19 kN/m³SIA 267 §1.2.1
Resistance factor for concrete γc1.5§ 2.4.2.6
Resistance factor for steel γs1.15§ 2.4.2.6
Duration factor ηt1.0 — both conditions of 4.2.1.3 met§ 4.2.1.3
Vertical force of the wall nd380 kN/m
Moment of the wall md20 kNm/m
Horizontal force, across the footing hd15 kN/m
Load factor on the weights of footing and soil γG1.35
Pressure distribution for the design of the concreteLinear, rigid footing (with lift-off)
Design bearing pressure of the soil (optional) qR,d420 kN/m²
Vertical force with the favourable loads (optional) nd,inf260 kN/mSIA 267 §5.4.1.2
Load factor on the weights, favourable γG,inf1.0SIA 267 §8.5.2.4 (35)
Angle of internal friction of the soil (optional) φ′k30 °
Base of the footingRough, failure in the soil: δ = φ′SIA 267 §8.4.1.1
Partial factor on tan φ′ γφ1.2SIA 267 §5.3.2.2 t.1
Partial factor on the sliding resistance γR1.0SIA 267 §8.5.2.1 (30)
Anchorage model of the transverse barsAt the wall face, from the bending moment§ 5.2.5
Ends of the transverse barsStraight§ 5.2.5.8
Vertical force of the wall n270 kN/m
Moment of the wall m10 kNm/m
Horizontal force h8 kN/m
Load caseQuasi-permanentTable 17
Settlement and tiltCalculated from the soil layersSIA 267 §8.5.4
Soil layers below the baseOne layer
Layer 1, compressibility fromModulus ME
Layer 1, compressibility modulus ME,130 MN/m²SIA 267 §1.2.1
Layer 1, effective unit weight γe,119 kN/m³
Depth that counts for the settlementAdded stress down to 20 % of the overburdenEN 1997-1 §6.6.2(6)
Admissible settlement (optional) sadm25 mmSIA 267 §8.5.4.1
Admissible tilt (optional) θadm2 mm/mSIA 267 §8.5.4.1
Tensile strength for crackingMean tensile strength (4.4.1.3)§ 4.4.1.3
Requirement levelNormal§ 4.4.2.2.3
Calculation: Section and weights
StepValueRef.
Effective depth, transverse barsh − c − Øt/2dt = 393 mm
Effective depth, longitudinal barsh − c − Øt − Øl/2dl = 381 mm
Steel area, transverse barsπ·Ø²/4·1000/sas,t = 1,026 mm²/m
Steel area, longitudinal barsas,l = 393 mm²/m
Cracking moment per metrekt·fctm·h²/6, kt = 1/(1 + 0.5·h/3), h in mmcr = 91.0 kNm/m§ 4.4.1.3 (99)(100)
Weight of the footingγRC·B·hgf = 18.0 kN/m
Weight of the backfillγe·(B − tw)·Dsgs = 15.4 kN/m
Calculation: Loads at the base
StepValueRef.
Vertical force at the basend + γG·(gf + gs)EN,d = 425.1 kN/mSIA 267 §8.5.3.7
Moment at the basemd + hd·h + nd·ewmb = 26.8 kNm/m
Eccentricity of the resultantmb/EN,d; central third: |e| ≤ B/6e = 0.063 m
Effective widthB − 2·|e|B′ = 1.474 mEN 1997-1 D.1
Calculation: Check 1 — bearing resistance of the soil
StepValueRef.
Bearing on the effective widthEN,d/(qR,d·B′)η = 0.687 · Pass69 % of the capacity usedSIA 267 §8.5.3.5 (37)
Calculation: Check 2 — overturning of the footing
StepValueRef.
Vertical force with the favourable loadsnd,inf + γG,inf·(gf + gs)EN,d,inf = 293.4 kN/m
Eccentricity of the resultantmb/EN,d,infed = 0.091 m
Overturning: resultant within the admissible eccentricityed/egrη = 0.171 · Pass17 % of the capacity usedSIA 267 §8.5.3.6 (38)
Calculation: Check 3 — sliding on the base
StepValueRef.
Friction angle of the baseφ′k ≤ 35°δk = 30.00 °SIA 267 §8.4.1.1 (27)
Design friction angle of the baseatan(tan δk/γφ)δd = 25.69 °SIA 267 §8.5.2.2
Design sliding resistanceEN,d,inf·tan δd/γR, c′ not countedRT,d = 141.2 kN/mSIA 267 §8.5.2.2 (31)
Sliding on the baseET,d/RT,dη = 0.106 · Pass11 % of the capacity usedSIA 267 §8.5.3.4 (36)
Calculation: Soil pressure for the design of the concrete
StepValueRef.
Largest soil pressureEN,d/B·(1 + 6·|e|/B), trapezoidσd,max = 328.4 kN/m²
Part of the base in contact100 % while |e| ≤ B/6bc/B = 100 %
Weights on the footingγG·(γRC·h + γe·Ds), acting downwardsthe net pressure p − gd loads the cantileversgd = 30.6 kN/m²
Calculation: Design strengths
StepValueRef.
Factor for the brittleness of strong concrete(40/fck)^(1/3) ≤ 1ηfc = 1.000§ 4.2.1.2 (26)
Design compressive strength of the concreteηfc·ηt·fck/γcfcd = 20.0 N/mm²§ 2.4.2.3 (2)
Design yield strength of the steelfyk/γsfyd = 434.8 N/mm²§ 2.4.2.5 (4)
Design shear stress limit0.3·√fck/γcτcd = 1.10 N/mm²§ 2.4.2.4 (3)
Aggregate factor48/(16 + Dmax·min(1 ; (60/fck)²)) ≥ 1.2kg = 1.200§ 4.3.3.2.1 (37)
Calculation: Check 4 — bending at the wall face, transverse bars
StepValueRef.
Cantilever from the wall faceon the right sidea = 0.675 m
Design moment at the wall face∫(p − gd)·t dt over the cantilevermd = 63.8 kNm/m
Bending resistanceas·fyd·(d − 0.85·x/2), 0.85·x = as·fyd/fcdas = 1,026 mm²/m, x/d = 0.067mRd = 170.4 kNm/m§ 4.3.2.1
Bending at the wall facemd/mRdη = 0.375 · Pass37 % of the capacity used§ 4.3.2.1
Minimum reinforcement: no brittle failure at crackingmcr/mRdη = 0.534 · Pass53 % of the capacity used§ 4.3.1.2
Calculation: Check 5 — detailing of the bottom bars
StepValueRef.
Largest spacing of the transverse barsmin(1.2·h ; 300 mm)smax = 300 mm§ 5.5.3.1
Longitudinal bars needed20 % of the transverse barsas,l,min = 205 mm²/m§ 5.5.3.2
Smallest bar diameter in a footingrecommended value, National AnnexØmin = 8 mmEN 1992-1-1 §9.8.2.1(1)
Detailing of the bottom barsmax of the ratiosη = 0.800 · Pass80 % of the capacity used§ 5.5.3.1, 5.5.3.2
Calculation: Check 6 — shear, footing without stirrups
StepValueRef.
Design shear force at d/2 from the wall face∫(p − gd) dt beyond the sectionvd = 133.5 kN/m§ 4.3.3.2.1
Strain for the shear resistancefyd/Es·md/mRd, md = 32.7 kNm/m at the sectionεv = 0.407 ‰§ 4.3.3.2.2 (39)
Coefficient1/(1 + εv·d·kg)kd = 0.839§ 4.3.3.2.1 (36)
Shearvd/vRdη = 0.370 · Pass37 % of the capacity used§ 4.3.3.2.1 (35)
Calculation: Check 7 — anchorage of the transverse bars beyond the wall face
StepValueRef.
Bar stress needed at the wall facefyd·md/mRdσsd = 163 N/mm²
Anchorage length50·kcp·Ø·(σsd/435)^1.5·(25/fck)^0.5·(Ø/20)^(1/3)·(1.5·Ø/cd)^0.5 ≥ 10·Ø, kcp = 1.0, cd = 50 mm (105)lbd = 140 mm§ 5.2.5.6 (108)
Anchorage of the transverse barslbd/lavη = 0.224 · Pass22 % of the capacity used§ 5.2.5
Calculation: Soil pressure under the service load
StepValueRef.
Vertical force at the basen + gf + gsEN = 303.4 kN/m
Eccentricity of the resultante = 0.045 m
Largest soil pressureσmax = 221.5 kN/m²
Resultant in the central thirde/ekernη = 0.168 · Pass17 % of the capacity usedSIA 267 §8.5.4.7
Calculation: Check 8 — settlement and tilt
StepValueRef.
Effective overburden at the base, removed by the excavationγe·(Ds + h)σ′z0 = 20.0 kN/m²
Mean net pressureEN/B − σ′z0pnet = 169.7 kN/m²
Loaded length for the stress spreadlong strip, 40·BL = 64.0 m
Depth of the compressible zone below the baseΔσz under the centre = 0.2·σ′z0(z)zlim = 6.11 mEN 1997-1 §6.6.2(6)
Settlement under the centre line, flexible baseΣ Δσz·Δz/ME, Δσz from the loaded rectangle (Boussinesq)s0 = 14.6 mmEN 1997-1 F.1
Settlement of the rigid footingmean of the characteristic points at 0.37·B from the axiss = 12.9 mm
Tilt across the footingdifference of the settlements of the two edges at mid-length, divided by Bθ = 0.66 mm/mEN 1997-1 §6.6.2(15)
Settlements/sadmη = 0.516 · Pass52 % of the capacity usedSIA 267 §8.5.4.1
Tiltθ/θadmη = 0.328 · Pass33 % of the capacity usedSIA 267 §8.5.4.1
Calculation: Check 9 — stresses in the transverse bars (Table 17)
StepValueRef.
Service moment at the wall facenet service pressure over the cantileverm = 43.3 kNm/m
Cracking momentkt·fctm·h²/6mcr = 91.0 kNm/m§ 4.4.1.3 (99)
Bar stressuncracked section: αe·m·(d − x)/Iσs = 6 N/mm²
Crack limitation at crackingσs,r/fykη = 0.477 · Pass48 % of the capacity usedTable 17
Crack limitation under the quasi-permanent loadσs/fykη = 0.011 · Pass1 % of the capacity usedTable 17

How this module is verified

Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.

Questions

Where does q_R,d for a strip footing come from?

From the geotechnical report, or from the soil bearing resistance module for a strip. It is checked as EN,d ≤ qR,d · B′.

When does a strip footing need top bars?

Where the weight of footing and soil exceeds the soil pressure under a cantilever, so that the base lifts off. In the worked example the whole base stays in contact.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 262:2025 · Page updated: 5 November 2026