Isolated pad footing to SIA 262

The code governs which inputs appear and how every value is derived.

Member

Material properties, shared by every verification. The cross-section is not shared: SIA 262 works from the section as sized for each internal-force case, so it belongs to each verification and appears with it.

About this check

clauses, worked example and questions

Checks a rectangular reinforced concrete footing under one column, loaded by N, M and H, to SIA 262:2025 and SIA 267:2013: the soil with lift-off, the bending, shear and punching of the concrete, the anchorage of the bars, and in service the settlement, the tilt and the bar stresses. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You enter the footing Bx, By and h, the column and its offset, the backfill Ds, the bottom bars, the materials and the weights. For the ultimate state: Nd, Mx,d, My,d, Hx,d, Hy,d, γG, the pressure distribution, qR,d, and for overturning and sliding Nd,inf, γG,inf, φ′k and the base roughness. Then ke, any punching reinforcement, and the anchorage model. In service: the actions, σadm, up to three soil layers with t1, ME,1 and γe,1, and the crack requirements.

You get every check with its utilisation and clause, and the settlements at the four corners. With the Basic plan, it prints as an A4 calculation note.

Assumptions and limits

Worked example

A 2.6 × 2.6 m footing, h = 750 mm, under a 0.4 × 0.4 m column, with Ø16 at 150 mm both ways, fck = 30 N/mm², Nd = 2,400 kN, Mx,d = 150 kNm, Hx,d = 40 kN, qR,d = 450 kN/m², Nd,inf = 1,500 kN, φ′k = 30°, and in service N = 1,700 kN, Mx = 60 kNm on two soil layers. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Length of the footing in x Bx2.6 m
Length of the footing in y By2.6 m
Thickness of the footing h750 mm
Column side in x cx0.4 m
Column side in y cy0.4 m
Soil cover above the footing Ds0.45 m
Cover to the bottom bars c50 mm§ 5.2.2
Outer (lowest) layerBars along x
Bars along x, diameter Øx16 mm
Bars along x, spacing sx150 mm
Bars along y, diameter Øy16 mm
Bars along y, spacing sy150 mm
Top barsNone
Characteristic compressive strength fck30 N/mm²§ 3.1.2.2.2
Mean tensile strength fctm2.9 N/mm²§ 3.1.2.2.4
Modulus of elasticity Ecm33600 N/mm²§ 3.1.2.3.3
Largest aggregate size Dmax32 mm§ 4.3.3.2.1
Characteristic yield strength fyk500 N/mm²§ 3.2.2.2
Modulus of elasticity Es205000 N/mm²§ 3.2.2.4
Unit weight of the reinforced concrete γRC25 kN/m³
Unit weight of the backfill γe19 kN/m³SIA 267 §1.2.1
Resistance factor for concrete γc1.5§ 2.4.2.6
Resistance factor for steel γs1.15§ 2.4.2.6
Duration factor ηt1.0 — both conditions of 4.2.1.3 met§ 4.2.1.3
Axial force of the column Nd2400 kN
Moment in x Mx,d150 kNm
Moment in y My,d0 kNm
Horizontal force in x Hx,d40 kN
Horizontal force in y Hy,d0 kN
Load factor on the weights of footing and soil γG1.35
Pressure distribution for the design of the concreteLinear, rigid footing (with lift-off)
Design moment per metreMean over the width of the footing
Design bearing pressure of the soil (optional) qR,d450 kN/m²
Axial force with the favourable loads (optional) Nd,inf1500 kNSIA 267 §5.4.1.2
Load factor on the weights, favourable γG,inf1.0SIA 267 §8.5.2.4 (35)
Angle of internal friction of the soil (optional) φ′k30 °
Base of the footingRough, failure in the soil: δ = φ′SIA 267 §8.4.1.1
Partial factor on tan φ′ γφ1.2SIA 267 §5.3.2.2 t.1
Partial factor on the sliding resistance γR1.0SIA 267 §8.5.2.1 (30)
Reduction for the moment transfer keSimplified value 0.9 (4.3.6.2.5)§ 4.3.6.2.5
Punching reinforcementNone§ 4.3.6.5
Anchorage model of the bottom barsAt the column face, from the bending moment§ 5.2.5
Ends of the bottom barsStraight§ 5.2.5.8
Axial force of the column N1700 kN
Moment in x Mx60 kNm
Moment in y My0 kNm
Horizontal force in x Hx20 kN
Horizontal force in y Hy0 kN
Load caseQuasi-permanentTable 17
Admissible soil pressure (optional) σadm300 kN/m²
Settlement and tiltCalculated from the soil layersSIA 267 §8.5.4
Soil layers below the baseTwo layers
Layer 1, thickness t12.5 m
Layer 1, compressibility fromModulus ME
Layer 1, compressibility modulus ME,140 MN/m²SIA 267 §1.2.1
Layer 1, effective unit weight γe,120 kN/m³
Layer 2, compressibility fromModulus ME
Layer 2, compressibility modulus ME,225 MN/m²SIA 267 §1.2.1
Layer 2, effective unit weight γe,210 kN/m³
Depth that counts for the settlementAdded stress down to 20 % of the overburdenEN 1997-1 §6.6.2(6)
Admissible settlement (optional) sadm30 mmSIA 267 §8.5.4.1
Admissible tilt (optional) θadm2 mm/mSIA 267 §8.5.4.1
Tensile strength for crackingMean tensile strength (4.4.1.3)§ 4.4.1.3
Requirement levelNormal§ 4.4.2.2.3
Calculation: Section and weights
StepValueRef.
Effective depth, bars along xh − c − Øx/2dx = 692 mm
Effective depth, bars along yh − c − Øx − Øy/2dy = 676 mm
Steel area, bars along xπ·Ø²/4·1000/sas,x = 1,340 mm²/m
Steel area, bars along yas,y = 1,340 mm²/m
Reinforcement ratiosas/(b·d)ρx ; ρy = 0.194 ; 0.198 %
Cracking moment per metrekt·fctm·h²/6, kt = 1/(1 + 0.5·h/3), h in mmcr = 241.7 kNm/m§ 4.4.1.3 (99)(100)
Weight of the footingγRC·Bx·By·hGf = 126.8 kN
Weight of the backfillγe·(Bx·By − cx·cy)·DsGs = 56.4 kN
Calculation: Loads at the base
StepValueRef.
Vertical load at the baseNd + γG·(Gf + Gs)EN,d = 2,647.3 kNSIA 267 §8.5.3.7
Moment at the base, xMx,d + Hx,d·h + Nd·ec,xMx,b = 180.0 kNm
Moment at the base, yMy,d + Hy,d·h + Nd·ec,yMy,b = 0.0 kNm
Eccentricity of the resultantMb/EN,d; central kern: |ex|/Bx + |ey|/By ≤ 1/6ex ; ey = 0.068 ; 0.000 m
Effective area(Bx − 2·|ex|)·(By − 2·|ey|)A′ = 6.406 m²EN 1997-1 D.1
Calculation: Check 1 — bearing resistance of the soil
StepValueRef.
Bearing on the effective areaEN,d/(qR,d·A′)η = 0.918 · Pass92 % of the capacity usedSIA 267 §8.5.3.5 (37)
Calculation: Check 2 — overturning of the footing
StepValueRef.
Vertical load with the favourable loadsNd,inf + γG,inf·(Gf + Gs)EN,d,inf = 1,683.2 kN
Eccentricity of the resultantMb/EN,d,infed,x ; ed,y = 0.107 ; 0.000 m
Overturning: resultant within the admissible eccentricityed/egrη = 0.123 · Pass12 % of the capacity usedSIA 267 §8.5.3.6 (38)(39)
Calculation: Check 3 — sliding on the base
StepValueRef.
Horizontal force at the base√(Hx,d² + Hy,d²)ET,d = 40.0 kN
Friction angle of the baseφ′k ≤ 35°δk = 30.00 °SIA 267 §8.4.1.1 (27)
Design friction angle of the baseatan(tan δk/γφ)δd = 25.69 °SIA 267 §8.5.2.2
Design sliding resistanceEN,d,inf·tan δd/γR, c′ not countedRT,d = 809.8 kNSIA 267 §8.5.2.2 (31)
Sliding on the baseET,d/RT,dη = 0.049 · Pass5 % of the capacity usedSIA 267 §8.5.3.4 (36)
Calculation: Soil pressure for the design of the concrete
StepValueRef.
Largest soil pressureplane through the part in contact, no tensionσd,max = 453.1 kN/m²
Part of the base in contact100 % while the resultant stays in the central kernAc/A = 100 %
Weights on the footingγG·(γRC·h + γe·Ds), acting downwardsthe net pressure p − gd loads the cantileversgd = 36.9 kN/m²
Calculation: Design strengths
StepValueRef.
Factor for the brittleness of strong concrete(40/fck)^(1/3) ≤ 1ηfc = 1.000§ 4.2.1.2 (26)
Design compressive strength of the concreteηfc·ηt·fck/γcfcd = 20.0 N/mm²§ 2.4.2.3 (2)
Design yield strength of the steelfyk/γsfyd = 434.8 N/mm²§ 2.4.2.5 (4)
Design shear stress limit0.3·√fck/γcτcd = 1.10 N/mm²§ 2.4.2.4 (3)
Aggregate factor48/(16 + Dmax·min(1 ; (60/fck)²)) ≥ 1.2kg = 1.200§ 4.3.3.2.1 (37)
Calculation: Check 4 — bending in x, bottom bars along x
StepValueRef.
Cantilever from the column faceon the +x sideax = 1.100 m
Design moment at the column face∫(p − gd)·t dt over the cantilever, mean over the width Bymx,d = 241.3 kNm/m
Effective depthdx = 692 mm
Bending resistanceas·fyd·(d − 0.85·x/2), 0.85·x = as·fyd/fcdas = 1,340 mm²/m, x/d = 0.050mxRd = 394.8 kNm/m§ 4.3.2.1
Bending in xmx,d/mxRdη = 0.611 · Pass61 % of the capacity used§ 4.3.2.1
Minimum reinforcement in x: no brittle failure at crackingmcr/mxRdη = 0.612 · Pass61 % of the capacity used§ 4.3.1.2
Spacing of the bars along xsx/smaxη = 0.500 · Pass50 % of the capacity used§ 5.5.3.1
Calculation: Check 5 — bending in y, bottom bars along y
StepValueRef.
Cantilever from the column faceon the +y sideay = 1.100 m
Design moment at the column face∫(p − gd)·t dt over the cantilever, mean over the width Bxmy,d = 214.6 kNm/m
Effective depthdy = 676 mm
Bending resistanceas·fyd·(d − 0.85·x/2), 0.85·x = as·fyd/fcdas = 1,340 mm²/m, x/d = 0.051myRd = 385.5 kNm/m§ 4.3.2.1
Bending in ymy,d/myRdη = 0.557 · Pass56 % of the capacity used§ 4.3.2.1
Minimum reinforcement in y: no brittle failure at crackingmcr/myRdη = 0.627 · Pass63 % of the capacity used§ 4.3.1.2
Spacing of the bars along ysy/smaxη = 0.500 · Pass50 % of the capacity used§ 5.5.3.1
Calculation: Check 6 — shear in x, slab without stirrups
StepValueRef.
Design shear force at d/2 from the column face∫(p − gd) dt beyond the section, mean over the widthvx,d = 300.4 kN/m§ 4.3.3.2.1
Strain for the shear resistancefyd/Es·md/mRd, md = 114.9 kNm/m at the sectionεv = 0.617 ‰§ 4.3.3.2.2 (39)
Coefficient1/(1 + εv·d·kg)kd = 0.661§ 4.3.3.2.1 (36)
Shear in xvd/vRdη = 0.599 · Pass60 % of the capacity used§ 4.3.3.2.1 (35)
Calculation: Check 7 — shear in y, slab without stirrups
StepValueRef.
Design shear force at d/2 from the column face∫(p − gd) dt beyond the section, mean over the widthvy,d = 270.3 kN/m§ 4.3.3.2.1
Strain for the shear resistancefyd/Es·md/mRd, md = 103.0 kNm/m at the sectionεv = 0.567 ‰§ 4.3.3.2.2 (39)
Coefficient1/(1 + εv·d·kg)kd = 0.685§ 4.3.3.2.1 (36)
Shear in yvd/vRdη = 0.533 · Pass53 % of the capacity used§ 4.3.3.2.1 (35)
Calculation: Check 8 — punching around the column
StepValueRef.
Effective depth for punchingmean of the two bottom layersdv = 684 mm§ 4.3.6.2.1
Control perimeterat dv/2 from the columnu₀ = 3,749 mm§ 4.3.6.2.2
Net soil reaction inside the control section∫(p − gd) dA over 1.075 m²ΔVd = 381.3 kN§ 4.3.6.2.6
Design punching forceNd − ΔVdVd = 2,018.7 kN
Reduction for the moment transfercentred column, simplified valueke = 0.90§ 4.3.6.2.5
Effective control perimeterke·u₀u = 3,374 mm§ 4.3.6.2.3
Distance to zero momentfrom the column axis to the farther footing edge, where the radial moment vanishesrsx ; rsy = 1.30 ; 1.30 m
Width of the support strip1.5·√(rsx·rsy) ≤ min(Bx ; By)bs = 1.95 m§ 4.3.6.4.6 (61)
Mean moments in the support stripat the column faces, over bsmsd,x ; msd,y = 241.3 ; 214.6 kNm/m§ 4.3.6.4.5
Rotation of the footing1.5·(rs/d)·(fyd/Es)·(msd/mRd)^1.5, larger of x and yψ = 0.0029§ 4.3.6.4.1 (60)
Coefficient1/(0.45 + 0.18·ψ·d·kg) ≤ 2kr = 1.140§ 4.3.6.3.2 (59)
Punching without punching reinforcementVd/VRd,cη = 0.700 · Pass70 % of the capacity used§ 4.3.6.3.1 (58)
Calculation: Check 9 — anchorage of the bottom bars beyond the column face
StepValueRef.
Bar stress needed at the column face, bars along xfyd·md/mRdσsd = 266 N/mm²
Anchorage length, bars along x50·kcp·Ø · (σsd/435)^1.5 · (25/fck)^0.5 · (Ø/20)^(1/3) · (1.5·Ø/cd)^0.5 ≥ 10·Ø, kcp = 1.0 (bottom bars, good bond), cd = 50 mm (105)lbd = 224 mm§ 5.2.5.6 (108)
Anchorage of the bars along xlbd/lavη = 0.214 · Pass21 % of the capacity used§ 5.2.5
Bar stress needed at the column face, bars along yfyd·md/mRdσsd = 242 N/mm²
Anchorage length, bars along y50·kcp·Ø · (σsd/435)^1.5 · (25/fck)^0.5 · (Ø/20)^(1/3) · (1.5·Ø/cd)^0.5 ≥ 10·Ø, kcp = 1.0 (bottom bars, good bond), cd = 50 mm (105)lbd = 195 mm§ 5.2.5.6 (108)
Anchorage of the bars along ylbd/lavη = 0.186 · Pass19 % of the capacity used§ 5.2.5
Calculation: Soil pressure under the service load
StepValueRef.
Vertical load at the baseN + Gf + GsV = 1,883.2 kN
Eccentricity of the resultantex ; ey = 0.040 ; 0.000 m
Largest soil pressureσmax = 304.2 kN/m²
Part of the base in contactAc/A = 100 %
Resultant in the central kerne/ekernη = 0.092 · Pass9 % of the capacity usedSIA 267 §8.5.4.7
Soil pressure against the admissible valueσ/σadmη = 0.958 · Pass96 % of the capacity used
Calculation: Check 10 — settlement and tilt
StepValueRef.
Effective overburden at the base, removed by the excavationγe·(Ds + h)the pressure above it loads the ground: net pressure p − σ′z0σ′z0 = 22.8 kN/m²
Mean net pressureEN/(Bx·By) − σ′z0pnet = 255.8 kN/m²
Depth of the compressible zone below the baseΔσz under the centre = 0.2·σ′z0(z)zlim = 5.83 mEN 1997-1 §6.6.2(6)
Settlement under the centre, flexible baseΣ Δσz·Δz/ME, Δσz from the loaded rectangle (Boussinesq)s0 = 17.5 mmEN 1997-1 F.1
Settlement of the rigid footingmean of the four characteristic points at 0.37·B from the centres = 12.8 mm
Settlements at the cornerscorners (−x,−y), (+x,−y), (+x,+y), (−x,+y)s1…4 = 7.3 ; 7.9 ; 7.9 ; 7.3 mmEN 1997-1 §6.6.2(15)
Tilt of the footingdifference of the corner settlements across the footing, divided by its sideθx ; θy = 0.20 ; 0.00 mm/mEN 1997-1 §6.6.2(15)
Settlements/sadmη = 0.425 · Pass43 % of the capacity usedSIA 267 §8.5.4.1
Tiltθ/θadmη = 0.100 · Pass10 % of the capacity usedSIA 267 §8.5.4.1
Calculation: Check 11 — bar stresses in x (Table 17)
StepValueRef.
Service moment at the column facemean over the widthmx = 163.1 kNm/m
Cracking momentkt·fctm·h²/6, kt = 1/(1 + 0.5·h/3)mcr = 241.7 kNm/m§ 4.4.1.3 (99)
Bar stressuncracked section: αe·m·(d − x)/Iσs = 9 N/mm²
Crack limitation at cracking, bars along xσs,r/fykη = 0.547 · Pass55 % of the capacity usedTable 17
Crack limitation under the quasi-permanent load, bars along xσs/fykη = 0.017 · Pass2 % of the capacity usedTable 17
Calculation: Check 12 — bar stresses in y (Table 17)
StepValueRef.
Service moment at the column facemean over the widthmy = 152.0 kNm/m
Cracking momentkt·fctm·h²/6, kt = 1/(1 + 0.5·h/3)mcr = 241.7 kNm/m§ 4.4.1.3 (99)
Bar stressuncracked section: αe·m·(d − x)/Iσs = 8 N/mm²
Crack limitation at cracking, bars along yσs,r/fykη = 0.560 · Pass56 % of the capacity usedTable 17
Crack limitation under the quasi-permanent load, bars along yσs/fykη = 0.015 · Pass2 % of the capacity usedTable 17

How this module is verified

Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.

Questions

Where does q_R,d come from?

From the geotechnical report, or from the soil bearing resistance module, which gives qR,d per unit of effective area.

Linear or uniform soil pressure?

Linear treats the footing as rigid and concentrates the pressure when the base lifts off. Uniform matches the bearing check on A′.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 262:2025 · Page updated: 29 October 2026