Structural Engineering Tools

Reinforced concrete column serviceability to SIA 262

Checks a rectangular or circular reinforced concrete column under compression and bending in service, to SIA 262:2025: concrete stress and creep, the long-term transfer of the load to the bars by creep and shrinkage, the axial shortening, and crack control where the moment opens the section. Every step shows its formula and the clause it comes from.

Basic SIA 262:2025

Part of the Basic plan

This module is included in the Basic plan and above, with its calculation note.

About this check

clauses, worked example and questions

Checks a rectangular or circular reinforced concrete column under compression and bending in service, to SIA 262:2025: concrete stress and creep, the long-term transfer of the load to the bars by creep and shrinkage, the axial shortening, and crack control where the moment opens the section. Every step shows its formula and the clause it comes from.

What it checks

  • Section and materials: Ac, As, ρ, the idealised area Ai = Ac + (αe − 1) · As, and fcm = fck + 8, clause 3.1.2.2.3, equation (6).
  • Combinations: quasi-permanent, frequent and characteristic values of N and M from the permanent and variable parts.
  • State of the section: the largest stress under the characteristic combination, uncracked, σc,max = N/Ai ± M/Wi, with fct,eff = kt · fctm, clause 4.4.1.3, equations (99) and (100).
  • Concrete compression, check 1: σc,qp ≤ 0.6 · fcm (3.1.2.6.3), the range of the creep model.
  • Transfer of the sustained force to the bars: the change of the concrete stress by creep and shrinkage, Δσc = −(σc0 · φ − εcs · Ecm) · αe · ρn / (1 + αe · ρn · (1 + χ · φ)), with the age-adjusted modulus Ec,adj = Ecm/(1 + χ · φ); then σc,∞, σs,∞ and the share of Nqp carried by the concrete, at loading and in the long term.
  • Bars stay elastic, check 2 (optional): σs,∞,max ≤ fyk, the most compressed bar including the bending part under Mqp. This is a plausibility criterion of the module, not a clause.
  • Axial shortening: ε0 = Nqp/(Ecm · Ai) and ε∞ = σs,∞/Es, then Δl0 and Δl∞ over the height l.
  • Crack control to Table 17, with wnom = 0.5 mm (increased) or 0.2 mm (high), only where the moment opens the section.

What you enter and what you get

You enter the shape (rectangle or circle), h in the plane of the moment and b, the optional height l, the bars along each face, Ø, c and Øw, and the materials. For creep and shrinkage: RH, the cement class, t0, t and ts, or your own φ and εcs. You enter NG, NQ, MG and MQ as characteristic values, compression positive, with ψ1 and ψ2. Then the requirement level and the ageing coefficient χ, computed as √t0/(1 + √t0) or entered.

You get φ and εcs, the stresses at loading and in the long term, the shortenings, and each check with its utilisation. With the Basic plan, it prints as an A4 calculation note.

Assumptions and limits

  • The moment is entered at the section checked, with the eccentricities and second-order effects of your own analysis under service loads.
  • φ follows EN 1992-1-1 Annex B and εcs EN 1992-1-1 §3.1.4. The creep coefficient is valid for compressive stresses up to 0.45 · fck at loading.
  • If the section stays compressed under every combination, no crack reinforcement is needed (4.4.2.3.5) and the Table 17 checks are not made.
  • Once the bars yield, the concrete takes all further creep.
  • For exposure classes XD, XF and XS, a limit of k1 · fck under the characteristic combination can be added, to EN 1992-1-1 §7.2(2). SIA 262 has no such limit.

Worked example

A 400 × 400 mm column 3.2 m high with 8Ø20, fck = 30 N/mm², NG = 1,600 kN, NQ = 600 kN, MG = 20 kNm and MQ = 15 kNm, at 50 % relative humidity. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Shape of the columnRectangle
Depth in the plane of the moment h400 mm
Width b400 mm
Height of the column (optional) l3.2 m
Bars along each face of width b (corners included) nb3
Bars along each side face (corners included) nh3
Bar diameter Ø20 mm
Concrete cover to the ties c30 mm
Tie diameter Øw8 mm
Characteristic compressive strength fck30 N/mm²§ 3.1.2.2.2
Mean tensile strength fctm2.9 N/mm²§ 3.1.2.2.4
Modulus of elasticity Ecm32000 N/mm²§ 3.1.2.3.3
Characteristic yield strength fyk500 N/mm²
Modulus of elasticity Es205000 N/mm²
Resistance factor for steel γs1.15§ 2.4.2.6
Creep coefficient φComputed (EN 1992-1-1 Annex B)§ 3.1.2.6
Relative humidity of the environment RH50 %
Cement classN — normal hardening
Age of the concrete at loading t028 days
Age considered (service life) t50 years
Shrinkage strain εcsComputed (EN 1992-1-1 §3.1.4)§ 3.1.2.7
Age at the end of curing ts7 days
Compression force, permanent part NG1600 kN
Compression force, variable part NQ600 kN
Bending moment, permanent part MG20 kNm
Bending moment, variable part MQ15 kNm
Combination factor, frequent ψ10.5
Combination factor, quasi-permanent ψ20.3
Requirement levelNormal§ 4.4.2.2.3
Tensile strength for the first crackMean tensile strength (4.4.1.3)§ 4.4.1.3
Exposure to chlorides, frost or sea water?No — X0 or XCEN 1992-1-1 §7.2(2)
Ageing coefficient χComputed, χ = √t₀/(1 + √t₀)
Check that the bars stay elastic in the long term?Yes
Calculation: Section
StepValueRef.
Gross concrete areab·hAc = 160,000 mm²
Bars8Ø20As = 2,513 mm²
Reinforcement ratioAs/Acρ = 1.57 %
Concrete area net of the barsAc − AsAc,n = 157,487 mm²
Distance of the bar axis to the facec + Øw + Ø/2a = 48 mm
Calculation: Materials
StepValueRef.
Mean compressive strengthfck + 8fcm = 38.0 N/mm²§ 3.1.2.2.3 (6)
Design yield strength of the barsfyk/γsfyd = 434.8 N/mm²§ 2.4.2.5 (4)
Modular ratioEs/Ecmαe = 6.41
Idealised areaAc + (αe − 1)·AsAi = 173,587 mm²
Calculation: Creep
StepValueRef.
Notional size2·Ac/u, u = 1,600 mm (perimeter)h0 = 200 mmEN 1992-1-1 Annex B (B.6)
Humidity factor[1 + (1 − RH/100)/(0.1·∛h0)·α1]·α2φRH = 1.778EN 1992-1-1 Annex B (B.3)
Strength factor16.8/√fcmβ(fcm) = 2.725EN 1992-1-1 Annex B (B.4)
Age at loading adjusted for the cementt0·(9/(2 + t0^1.2) + 1)^α ≥ 0.5, α = 0t0,adj = 28.0 daysEN 1992-1-1 Annex B (B.9)
Age factor1/(0.1 + t0^0.2)β(t0) = 0.488EN 1992-1-1 Annex B (B.5)
Notional creep coefficientφRH·β(fcm)·β(t0)φ0 = 2.366EN 1992-1-1 Annex B (B.2)
Humidity–size coefficient1.5·[1 + (0.012·RH)^18]·h0 + 250·α3 ≤ 1500·α3βH = 540 daysEN 1992-1-1 Annex B (B.8)
Development with time[(t − t0)/(βH + t − t0)]^0.3, t = 18,250 daysβc(t, t0) = 0.991EN 1992-1-1 Annex B (B.7)
Creep coefficientφ0·βc(t, t0)valid for compressive stresses up to 0.45·fck at loadingφ(t, t0) = 2.35EN 1992-1-1 Annex B (B.1)
Calculation: Shrinkage
StepValueRef.
Humidity factor1.55·[1 − (RH/100)³]βRH = 1.356EN 1992-1-1 Annex B (B.12)
Basic drying shrinkage0.85·[(220 + 110·αds1)·exp(−αds2·fcm/10)]·10⁻⁶·βRHεcd,0 = 0.482 ‰EN 1992-1-1 Annex B (B.11)
Size coefficientfrom h0, linear between the values of Table 3.3kh = 0.850EN 1992-1-1 §3.1.4(6)
Development of drying(t − ts)/[(t − ts) + 0.04·√h0³]βds(t, ts) = 0.994EN 1992-1-1 §3.1.4 (3.10)
Drying shrinkageβds·kh·εcd,0εcd = 0.407 ‰EN 1992-1-1 §3.1.4 (3.9)
Final autogenous shrinkage2.5·(fck − 10)·10⁻⁶εca,∞ = 0.050 ‰EN 1992-1-1 §3.1.4 (3.12)
Autogenous shrinkage[1 − exp(−0.2·√t)]·εca,∞εca = 0.050 ‰EN 1992-1-1 §3.1.4 (3.11)
Total shrinkage strainεcd + εcaεcs = 0.457 ‰EN 1992-1-1 §3.1.4 (3.8)
Calculation: Combinations
StepValueRef.
Quasi-permanentG + ψ2·QNqp ; Mqp = 1,780 ; 24.5 kN ; kNm
FrequentG + ψ1·QNfr ; Mfr = 1,900 ; 27.5 kN ; kNm
CharacteristicG + QNra ; Mra = 2,200 ; 35.0 kN ; kNm
Calculation: State of the section
StepValueRef.
Size factor1/(1 + 0.5·t), t = smallest dimension in mkt = 0.833§ 4.4.1.3 (100)
Effective tensile strengthkt·fctmfct,eff = 2.42 N/mm²§ 4.4.1.3 (99)
Largest stress, characteristic combination, uncrackedN/Ai ± M/Wi (tension positive)the whole section stays compressedσc,max = -9.72 N/mm²
Calculation: Check 1 — concrete compression under the quasi-permanent load
StepValueRef.
Largest compression at loadinguncracked section, Ecm|σc,qp| = 12.32 N/mm²
Stress–strength ratio|σc|/fcm = 0.324
Concrete compression within the range of the creep model|σc,qp|/(0.6·fcm)η = 0.540 · Pass54 % of the capacity used§ 3.1.2.6.3
Calculation: Transfer of the sustained force to the bars
StepValueRef.
Creep coefficient usedfrom the section partφ = 2.35
Ageing coefficient√t0/(1 + √t0)χ = 0.841
Age-adjusted effective modulusEcm/(1 + χ·φ)Ec,adj = 10,764 N/mm²
Concrete stress at loading (centric part)−Nqp/Aiσc0 = -10.25 N/mm²
Bar stress at loadingαe·σc0σs0 = -65.7 N/mm²
Change of the concrete stress by creep and shrinkage−(σc0·φ − εcs·Ecm)·αe·ρn/(1 + αe·ρn·(1 + χ·φ)), ρn = As/Ac,npositive: the concrete is relievedΔσc = 3.03 N/mm²
Long-term concrete stressσc0 + Δσcσc,∞ = -7.22 N/mm²
Long-term bar stressσs0 − Δσc·Ac,n/Asσs,∞ = -255.8 N/mm²
Share of Nqp carried by the concreteat loading → long termFc/Nqp = 91 % → 64 %
Calculation: Check 2 — the bars stay elastic in the long term
StepValueRef.
Most compressed bar, long term|σs,∞| + bending part under Mqp (Ec,eff)|σs,∞,max| = 282 N/mm²
Bars below yield under the sustained load|σs,∞,max|/fykη = 0.564 · Pass56 % of the capacity used
Calculation: Axial shortening
StepValueRef.
Instantaneous strainNqp/(Ecm·Ai)ε0 = 0.320 ‰
Long-term strain|σs,∞|/Es (the bars and the concrete shorten together)ε∞ = 1.248 ‰
Instantaneous shorteningε0·lΔl0 = 1.03 mm
Long-term shorteningε∞·lof which 2.97 mm after loading (creep and shrinkage)Δl∞ = 3.99 mm

How this module is verified

Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.

Questions

Why do the bars carry more load with time?

Creep and shrinkage shorten the concrete, and the bars shorten with it. In the worked example the concrete share of Nqp falls from 91 % at loading to 64 % in the long term.

Why compare the shortenings of neighbouring members?

Differences of shortening between neighbouring columns, or between columns and cores, load the slabs and the partitions they carry.

Which plan includes this module?

The Basic plan, with its calculation note.

Related

Norm: SIA 262:2025 · Page updated: 29 October 2026