Composite steel–concrete beam in bending to SIA 264

The code governs which inputs appear and how every value is derived.

Member

Material and cross-section, shared by every verification. Change the verification above and these stay as they are.

About this check

clauses, worked example and questions

Checks a steel beam acting with a concrete slab, to SIA 264:2014: the bare steel beam at the construction stage, the composite section at the final stage, the shear connection and the deflection in service. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You choose a sagging or a hogging section and the scope: the full member, or one section only. You enter the materials and resistance factors, the slab (solid, or composite with the sheeting across or along the beam), the steel profile, the span, the beam spacings and how beff and l0 are found. You enter the forces at the construction stage with the lateral restraints, the forces at the final stage, the studs and the ribs, the serviceability moments, the load shape, the deflection limit and the shrinkage data.

You get every resistance, the stud number and spacing, both deflections and the utilisation of each check with a pass or fail. With the Basic plan, it prints as an A4 calculation note.

Assumptions and limits

Worked example

A sagging section of an 11 m interior beam at 2,000 mm spacing, a rolled profile 300 mm deep with a 150 mm flange, under a 150 mm composite slab on 40 mm ribs across the beam, fy = 235 N/mm² and fck = 30 N/mm², 16 mm studs, with MEd = 52 kNm at casting and 314 kNm at the final stage. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Characteristic yield strength fy235 N/mm²SIA 263 tab. 1
Modulus of elasticity Ea210000 N/mm²
Resistance factor, steel γa1.05
Characteristic cylinder strength fck30 N/mm²SIA 262 tab. 3
Aggregate coefficient kE10700
Resistance factor, concrete γc1.5
Yield strength of the reinforcement fsk500 N/mm²
Resistance factor, reinforcement γs1.15
The section isSagging — in the span, the slab compressed§ 4.3.2.1
Scope of the calculationFull member — construction stage, final stage and serviceability§ 5.1.1.5
Type of slabComposite slab — sheeting perpendicular to the beam§ 5.1.2.7
Overall depth of the slab ht150 mm
Depth of the ribs of the sheeting hp40 mm§ 5.1.2.7
Depth of a haunch over the beam, if any e0 mm
ProfileRolled I or H profile
Overall depth ha300 mm
Flange width b150 mm
Flange thickness tf10.7 mm
Web thickness tw7.1 mm
Root radius r15 mm
Span of the beam l11 m
Position of the beam in the floorInterior beam — slab on both sidesSIA 262 §4.1.3.3.2
Spacing to the beam on the left, centre to centre aL2000 mmSIA 262 §4.1.3.3.2
Spacing to the beam on the right, centre to centre aR2000 mmSIA 262 §4.1.3.3.2
How the participating width is foundFrom l0 — SIA 262 (19) and (20)§ 4.3.1.2
How l0 is foundFrom the span and the supports — SIA 262 figure 11SIA 262 §4.1.3.3.3
Where along the beamEnd span — 0,85·l₁SIA 262 §4.1.3.3.3
Design bending moment MEd52 kNm§ 5.1.1.6
Design shear force VEd38 kN§ 5.1.1.6
Design axial force, if any NEd0 kN
Lateral-torsional bucklingChecked — SIA 263 §4.5.2SIA 263 §4.5.2
Distance between lateral restraints of the compressed flange lD5500 mmSIA 263 §4.5.2
Shape of the moment between those restraints ψTriangular, zero at one end — ψ = 0SIA 263 Annexe B
Design bending moment MEd314 kNm
Design shear force VEd115 kN§ 4.3.2.2
Design axial force, if any NEd0 kN
Resistance of the composite sectionFrom the section class — SIA 264 table 2§ 4.2.1.1
Type of connectorHeaded studs, welded§ 6.1.1.3
Diameter of the stud d16 mm§ 6.1.2.1
Length of the stud, after welding hD100 mm§ 6.1.1.3
Tensile strength of the stud steel fu450 N/mm²§ 6.1.2.1
Resistance factor of the connection γv1.25§ 6.1.2.1
Connectors per cross-section n1§ 7.1.2
Mean width of the concrete ribs b0150 mm§ 6.1.3.2
Studs side by side in one rib Nr1§ 6.1.3.2
The studs areWelded through the sheeting§ 6.1.3.3
From the point of zero moment to the sectionHalf the span — from a support to midspan§ 6.1.2.3
Upper transverse bars, diameter Øt10 mm§ 5.1.4.2
Upper transverse bars, spacing sf,t150 mm§ 5.1.4.6
Angle of the compressed strut θfThe flattest the concrete allows — chosen here§ (7)
The sheetingNot counted§ 5.1.4.7
Bending moment on the steel beam alone Mser,a38 kNm§ 5.1.3.3
Bending moment on the composite beam Mser,b104 kNm§ 4.6.4
Shape of the loading, for the deflectionUniformly distributed load
Deflection limit, span divided by l/…350SIA 260 Annexe A
Effect of shrinkageConsidered§ 5.1.3.1
Specific shrinkageComputed from the humidity, the section and the ageSIA 262 §3.1.2.7
Relative humidity of the surroundings RH70 %SIA 262 §3.1.2.7
CementNormal hardening (CEM 32,5 R, 42,5 N)SIA 262 §3.1.2.7
Age at which the shrinkage is wanted t18250 daysSIA 262 §3.1.2.7
Age at the end of curing ts7 daysSIA 262 §3.1.2.7
Quasi-permanent load on the beam, for the frequency g + ψ2·q12 kN/m§ 5.1.3.5
Calculation: Resistance of one headed stud
StepValueRef.
Modulus of the concretekE·∛fcm, with fcm = fck + 8Ecm = 35,973 N/mm²SIA 262 §3.1.2.3.3
Crushing of the concrete0,29·d²·√(fck·Ecm)/γv — the concrete bearing against the stud.PRd | concrete = 61.7 kN§ (30)
Rupture of the shank0,8·fu·(π·d²/4)/γv, with fu at most 500 N/mm² — 450 with profiled sheeting.PRd | shank = 57.9 kN§ (31)
Resistance of one studthe shank governsPRd,0 = 57.9 kN§ 6.1.2.1
Reduction, ribs perpendicular to the beam(0,70/√Nr)·(b0/hp)·(hD/hp − 1), Nr studs side by side in a rib.capped at 0.85, §6.1.3.3αt = 0.850§ (33)
Design resistance of one studPRd = 49.2 kN§ 6.1.3
Tension the stud may take without a testabove it, the resistance comes from tests0,1·PRd = 4.9 kN§ 6.1.2.2
Calculation: Slab
StepValueRef.
Overall depth of the slabht = 150 mm
Depth of the ribshp = 40 mm§ 5.1.2.7
Participating depth of the slabht − hp. With the sheeting perpendicular to the beam only the concrete above the ribs is counted, so the participating depth is the overall depth less the rib depth.hc = 110 mm§ 5.1.2.7
Calculation: Steel section
StepValueRef.
Clear depth of the webha − 2·tfhw = 278.6 mm
Area of the steel sectionThe two flanges, the web and the four root fillets, the last taken as (4 − π)·r² with their centroid at 0,2234·r from the junction.Aa = 5,381 mm²
Of which the root filletsThe fillets are carried as a plate in the stack, so the area, the centroid and the inertia stay consistent with each other wherever the steel is decomposed geometrically.3.7 % of the plate modelAa − Aa,plate = 193 mm²
Centroid above the bottom fibreha/2 for a symmetric section.za = 150.0 mm
Second moment of areaIy = 83,560,262 mm⁴
Elastic section modulus, bottom fibreWy,el = 557,068 mm³
Plastic section modulusTaken about the equal-area axis of the plate stack, which is the plastic neutral axis of the bare profile.Wy,pl = 628,356 mm³
The plate stack against the closed-form propertiesThe same section is built twice, once as a stack of plates and once from the closed form, and the two are reported against each other rather than one being trusted.ΔWy,pl = -0.00 %ΔIy = 0.00 %
Second moment of area, weak axisIz = 6,036,258 mm⁴
Torsion constantΣb·t³/3 plus the junction term 2·α·D⁴, which the thin-plate sum alone leaves out — on a rolled profile that is some 20 % of It.It = 205,969 mm⁴
Compressed flange outstandIn the span the upper flange is the compressed one.class 1, limits 9.0 / 10.0 / 14.0c/t = 5.28SIA 263 tab. 5b
Web in bendingclass 1, limits 72.0 / 83.0 / 124.0hw/tw = 35.01SIA 263 tab. 5a
Class of the bare steel sectionThe worse of the two plates. It is the class of the section ALONE, which is what governs while the slab is being cast and what table 2 of SIA 264 reads to decide which method is allowed.class = 1SIA 263 tab. 5a, 5b
Calculation: Participating width
StepValueRef.
Determining spanFigure 11 of SIA 262 reads the distance between points of zero moment straight off the spans.End span, 0,85·l₁l0 = 9,350 mmSIA 262 §4.1.3.3.3
Half the clear distance, left side(a − b)/2 — the flange width is not counted in it.b1 = 925 mmSIA 262 §4.1.3.3.2
Participating strip, left side0,2·bi + 0,1·l0 governsbeff,1 = 1,120 mmSIA 262 (20)
Half the clear distance, right side(a − b)/2 — the flange width is not counted in it.b2 = 925 mmSIA 262 §4.1.3.3.2
Participating strip, right side0,2·bi + 0,1·l0 governsbeff,2 = 1,120 mmSIA 262 (20)
Sum over the flangeΣbeff,i + bw = 2,390 mmSIA 262 (19)
Participating widthcapped by the slab actually therebeff = 2,000 mm§ 4.3.1.2
Eurocode 4's simplified width, for comparison0.0 % against the Swiss widthl0/4 = 2,000 mmEN 1994-1-1 §5.4.1.2
Overall depth of the composite sectionha + e + hth = 450 mm§ 5.1.2.2
Participating area of the slabbeff · hcAc = 220,000 mm²
Calculation: Common values
StepValueRef.
Section modulus for the classClasses 1 and 2 take Wy,pl, class 3 Wy,el and class 4 Weff,y from the reduced section.Wy,pl = 628,356 mm³SIA 263 §4.5.2.2
Bending resistance of the steel beamfy·W/γaMa,Rd = 140.6 kNmSIA 263 §5.1
Calculation: Check 1 — bending of the steel beam
StepValueRef.
Bending at the construction stageMEd ≤ Ma,Rdη = 0.370 · Pass37 % of the capacity used§ 5.1.1.6
Calculation: Check 2 — lateral-torsional buckling
StepValueRef.
Moment-shape factor1,75 − 1,05·ψ + 0,3·ψ², with ψ = 0.00. A moment that falls away between the restraints raises the critical moment.η = 1.750SIA 263 Annexe B
Critical buckling stress√(σDv² + σDw²) — the uniform-torsion and the warping parts combined. σDv = 231.0, σDw = 187.1 N/mm²; the uniform part dominates here.σcr,D = 297.2 N/mm²SIA 263 Annexe B
Critical momentMcr = 186.8 kNmSIA 263 Annexe B
Slenderness for buckling√(W·fy/Mcr)λ̄D = 0.889SIA 263 §4.5.2.3
Imperfection factorrolled profileαD = 0.21SIA 263 §4.5.2.3
Reduction factor1/(ΦD + √(ΦD² − λ̄D²)) ≤ 1,0, with ΦD = 0,5[1 + αD(λ̄D − 0,4) + λ̄D²].χD = 0.786SIA 263 (10)
Buckling resistanceχD·W·fy/γM1MD,Rd = 110.6 kNmSIA 263 (9)
Lateral-torsional buckling at the construction stageMEd ≤ MD,Rdη = 0.470 · Pass47 % of the capacity usedSIA 263 §4.5.2.1
Calculation: Check 3 — shear of the steel web
StepValueRef.
Shear areaAv = 2,568 mm²SIA 263 §4.4
Shear resistanceAv·fy/(√3·γa)VRd = 331.9 kNSIA 263 §4.4
Shear at the construction stageVEd ≤ VRdη = 0.115 · Pass11 % of the capacity usedSIA 263 §4.4
Calculation: Common values
StepValueRef.
Resistance modelTable 2 of SIA 264 ties the method to the class of the section: plastic for classes 1 and 2, elastic for class 3, elastic on the reduced section for class 4.class 1 → PP or EP– = Plastic (PP / EP)§ 4.2.1.1
Stud spacing for the flange to count as class 1§4.2.2.3: where the connection to the slab removes the risk of local buckling of the compressed flange, that flange may be taken as class 1 provided the studs are no further apart than this — 15·tf·ε for a composite slab whose sheeting runs perpendicular to the beam, and no more than 9·tf·ε from the stud to the flange edge.≤ 22·tf·ε = 235 mm§ 4.2.2.3
Stud spacing, sheeting perpendicular≤ 15·tf·ε = 161 mm§ 4.2.2.3
Stud to the outer edge of the flange≤ 9·tf·ε = 96 mm§ 4.2.2.3
Calculation: Plastic resistance
StepValueRef.
Design strength of the steelfy/γa = 223.8 N/mm²§ 4.1.5
Design strength of the concrete in the blockThe 0,85 is inside the plastic block, not in fcd.0,85·fck/γc = 17.00 N/mm²§ 5.1.2.1
Force the steel section can develop(fy/γa)·AaFa = 1,204 kN§ 5.1.2.1
Force the participating slab can develop0,85·(fck/γc)·beff·hcFc,max = 3,740 kN§ 5.1.2.1
Plastic neutral axis lies in the– = slab§ 5.1.2.1
Plastic neutral axis above the bottom fibrezb,pl = 414.6 mm
Depth of concrete in compression7.9 % of hxp = 35.4 mm§ 5.1.2.2
Lever arm of the plastic coupleBetween the centroid of the compression and that of the tension.a = 282.3 mm
Plastic resistance of the composite sectionMpl,Rd = 340.0 kNm§ 5.1.2.1
Local stability of the steel sectionThe plastic neutral axis falls in the slab, so the whole steel profile is in TENSION and there is nothing in it to buckle.– = not in question§ 4.2.1.1
The same resistance on a fillet-free plate modelThe four root fillets are some 3 to 4 % of the area of a rolled profile and they sit close to the web, where a hogging section needs them most. This module places them geometrically and counts them; a tabulated relation that decomposes the steel into rectangles cannot, and has to drop them. The value above is the one to use — the plate model is here because an older calculation will have used it.3.5 % below the value aboveMpl,Rd | r = 0 = 328.5 kNm
Calculation: Longitudinal shear force
StepValueRef.
Force the connection has to transmit(fy/γa)·Aa — the plastic neutral axis is in the slab.the steel yields; the slab is only partly compressedVl,Ed = 1,204 kN§ 6.1.1.2
Length over which it is transmittedFrom the point of zero moment to the critical section.half the spanlv = 5,500 mm§ 6.1.2.3
Calculation: Number and spacing
StepValueRef.
Connectors requiredrounded up to 25N = Vl,Ed/PRd = 24.47§ 6.1.2.1
Cross-sections with 1 connectorN/n = 25
Largest uniform spacing§6.1.2.3 lets flexible connectors be spaced evenly between two critical sections in a sagging zone — for a doubly symmetric steel section, a plastic resistance and a shear force of one sign.e = lv/(N/n) = 220 mm§ 6.1.2.3
Resistance of the connectionVl,Ed ≤ N·PRdη = 0.979 · Pass98 % of the capacity used§ 6.1.2.1
Least degree of connection a partial connection may have§6.1.1.6 allows partial connection in a sagging zone with a plastic section. The beam's resistance then falls with the degree of connection — this module designs TOTAL connection and checks the beam with it.Le = 9.4 m — at least 10 of the 25N/Nf ≥ = 0.40§ (29)
Calculation: Detailing of the studs
StepValueRef.
Spacing along the beam, at least 5·de > 5·dη = 0.364 · Pass36 % of the capacity used§ 7.1.2
Spacing along the beam, at most min(6·ht; 800 mm)e ≤ 800η = 0.275 · Pass28 % of the capacity used§ 7.1.3
Shank to the edge of the flange, at least 20 mmc ≥ 20 mmη = 0.299 · Pass30 % of the capacity used§ 7.1.7
Flange thickness against the studtf/d ≥ 0,5η = 0.748 · Pass75 % of the capacity used§ 7.1.4
Calculation: The surfaces of figure 3
StepValueRef.
Surface through the slabe-e: through the concrete above the ribs, crossed by the upper bars only.Lc = hc, Ae = Ate-e = 110 mm§ 5.1.4.2
Share of the force that crosses itLongitudinal equilibrium of the part of the slab beyond the surface: it receives the force only by crossing it, in proportion to the concrete it holds, (beff,i + b/2 − c)/(Σbeff,i + b), c the outer stud line from the axis.the left side, in the plane of the outer studsAc1/Ac = 0.500
Reduced concrete strengthkc = 0,55kc·fcd = 11.00 N/mm²§ (6)
Range of the strut anglefor a slab in compressionθf = 25° to 45°§ (7)
Calculation: Shear from the connection
StepValueRef.
Longitudinal shear per unit lengthVl,Ed/lv — the connectors evenly spacedvl,Ed = 219.0 kN/m§ 6.1.1.2
Calculation: Surface e-e, through the slab
StepValueRef.
Shear crossing itvEd = 109.5 kN/m§ 5.1.4.5
Angle of the compressed strutthe flattest permittedθf = 25.0 °§ (7)
Concrete strut, e-e, through the slabvsd ≤ kc·fcd·Lc·sinθf·cosθfη = 0.236 · Pass24 % of the capacity used§ (6)
Transverse bars the shear needsFrom vsd = (Ae/sf)·fsd·cotθf.At/sf,req = 117 mm²/m§ (5)
Transverse bars, e-e, through the slabvEd ≤ vsd + vpdη = 0.224 · Pass22 % of the capacity used§ (4)
Calculation: Transverse bars, shear and bending together
StepValueRef.
Calculation: Check 1 — bending of the composite section
StepValueRef.
Bending at the final stageMEd ≤ Mpl,Rdη = 0.924 · Pass92 % of the capacity used§ 5.1.2.1
What the slab is worthThe whole case for making the beam composite, in one number: how much more moment the section carries once the slab works with it.MRd/Ma,Rd = 2.42
Calculation: Check 3 — shear at the final stage
StepValueRef.
Shear at the final stageVEd ≤ VRdη = 0.347 · Pass35 % of the capacity used§ 4.3.2.2
Calculation: Common values
StepValueRef.
Equivalence coefficient for the serviceability sectionnel = 5.84§ 4.6.4
Inertia of the composite section4.81 × the steel beam aloneIb = 402,249,460 mm⁴§ 4.6.4
Deflection coefficientw = 5·M·l²/(48·E·I)a moment alone does not fix a deflection; the load shape doesw·E·I/(M·l²) = 0.1042
Deflection at casting, steel aloneon Ia, not Iblocked into the finished beam — this is what a precamber answerswa = 27.3 mm§ 5.1.3.3
Deflection of the composite beamw = 5·M·l²/(48·E·I)wb = 15.5 mm§ 4.6.4
Least precamber, if one is madeFor fabrication reasons a precamber is at least this; less is not made.L = 11,000 mm√(0,025·L) ≥ 10 mm = 16.6 mmSIA 263 §4.10.3.4
Calculation: Check 1 — deflection of the composite beam
StepValueRef.
Deflection under the serviceability loadwb ≤ l/350η = 0.494 · Pass49 % of the capacity usedSIA 260 Annexe A
Calculation: Check 2 — deflection including shrinkage
StepValueRef.
Notional size of the slab2·Ac/uone drying face — the sheeting closes the soffith0 = 220 mmSIA 262 §3.1.2.7.8
Autogenous shrinkage, final2,5·(fck − 10)·10⁻⁶the hydrating paste itself — no humidity enters itεca,∞ = 0.050 ‰EN 1992-1-1 §3.1.4
Drying shrinkage, unrestrainedβRH = 1.018 at RH 70 %εcd,0 = 0.362 ‰EN 1992-1-1 B
Size factorfrom h0kh = 0.830EN 1992-1-1 §3.1.4
Drying reached by t18,250 days, drying from 7βds = 0.993EN 1992-1-1 §3.1.4
Specific shrinkageεcd + εcaεcs = 0.348 ‰SIA 262 (15)
Modulus for a shrinkage-like actionEcm/2the nominal modulus for shrinkageEcs = 17,987 N/mm²§ 3.5.2
Tension the connection imposes on the slabεcs·Ecs·Acthe connection prevents the slab from shorteningNcs = 1,379 kN§ 5.1.3.1
Moment shrinkage producesNcs·(zc − zb)self-equilibrated: the slab in tension, the section saggingMcs = 38.1 kNm§ 5.1.3.1
Deflection shrinkage addsMcs·l²/(8·Ea·Ib)Mcs is constant along the beam — the shrinkage is uniformw(Mcs) = 6.8 mm§ 5.1.3.1
Deflection including shrinkagewb + w(Mcs) ≤ l/350η = 0.711 · Pass71 % of the capacity used§ 5.1.3.1
Calculation: Check — the steel stays elastic in service
StepValueRef.
Stress in the bottom fibre of the steelMser,a/Wa,inf + Mser,b·zb/Ib — the steel beam alone for what it carried while the slab was cast, the composite section for the rest.σa,ser = 163.2 N/mm²§ 5.1.3.1
The steel stays elastic in serviceσa,ser ≤ fyη = 0.694 · Pass69 % of the capacity used§ 5.1.3.1
Calculation: Vibrations
StepValueRef.
Stiffness for short-term vibrationn0 = Ea/Ecm = 5.84, no creepEa·Ib,0 = 84,472 kN·m²§ 4.6.4
First natural frequency, as a simple spanA continuous beam is stiffer and its frequency higher.m = 1.22 t/m from the quasi-permanent loadf1 = (π/2L²)·√(EI/m) = 3.41 Hz

How this module is verified

Verified clause by clause against SIA 264:2014 and against independent calculations used on real projects, before release.

Questions

What does the slab add?

In the worked example Mpl,Rd = 340.0 kNm against Ma,Rd = 140.6 kNm for the steel beam alone, a ratio of 2.42.

Why is one stud worth 49.2 kN?

The shank governs: 57.9 kN by equation (31) against 61.7 kN by equation (30). The ribs across the beam then reduce it by αt, capped at 0.85. Twenty-five studs at 220 mm carry Vl,Ed = 1,204.4 kN, η = 0.979.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 264:2014 · Page updated: 8 November 2026