Timber bearing at a support to SIA 265

The code governs which inputs appear and how every value is derived.

Member

Material and cross-section, shared by every verification. Change the verification above and these stay as they are.

About this check

clauses, worked example and questions

Checks the bearing of a solid-timber or glulam member on a support: compression perpendicular to the grain at the ultimate limit state, to SIA 265:2021. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You enter the wood type, strength class, load duration, service class and the width b of the member; the type of support; the contact area (bearing length lA and width bA, or the area directly); the design support reaction Rd; and the design compressive strength perpendicular to the grain fc,90,d from your copy of SIA 265.

You get the contact area, the design stress, the design resistance and the utilisation with a pass or fail, each with its clause. With the Basic plan, the same calculation prints as an A4 calculation note.

Assumptions and limits

Worked example

A glulam beam GL24h, 280 mm wide, in service class 1, bearing over 280 × 280 mm on a general support, with a design reaction of 37 kN. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Wood typeGlulam
Strength classGL24h
Load duration ηtShort to permanent§ 2.2.6
Service class ηw1§ 3.2.1.3 t.4
Section width b280 mm
Type of supportGeneral§ 3.3.2.1 t.8 / 3.4.2.2 t.9
Contact area given byBearing length and width
Bearing length lA280 mm
Bearing width bA280 mm
Design support reaction Rd37 kN
Design compressive strength ⟂ grain fc,90,d1.9 N/mm²§ 3.3.2.1 t.8 / 3.4.2.2 t.9
Load inclined to the grain?No — perpendicular§ 4.2.2.3
Calculation: Ultimate limit state
StepValueRef.
Contact areaA = lA · bAA = 78,400 mm²
Load duration factorηt = 1.00§ 2.2.6
Moisture factorηw = 1.00§ 3.2.1.3 t.4
Design stressσc,90,d = Rd / Aσc,90,d = 0.472 N/mm²
Design resistance ⟂ grainfRd = fc,90,d · ηt · ηwfRd = 1.900 N/mm²§ 4.2.2.2 (11)
Compression perpendicular to the grainσc,90,d ≤ fc,90,dη = 0.248 · Pass25 % of the capacity used§ 4.2.2.2 (11)
Alternative methodSIA 265 §4.2.2.2 allows the verification perpendicular to the grain to be carried out instead according to annex C. That method is not implemented here.SIA 265 annex C§ 4.2.2.2

How this module is verified

Verified clause by clause against SIA 265:2021 and against independent calculations used on real projects, before release.

Questions

Which strength do I enter for a support with front wood?

The value SIA 265 gives for the type of support you choose. The higher value for front wood and end supports is admissible only if the larger deformations do not impair the behaviour of the member.

Does it include the reduction of the contact area in fire?

Not here. The fire situation is a separate module that reduces the contact surface for charring.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 265:2021 · Page updated: 20 October 2026