Material properties, shared by every verification. The cross-section is not shared: SIA 263 classifies it from the internal forces, so it belongs to each verification and appears with it.
Checks the resistance of a steel section to an axial tensile force at the ultimate limit state, to SIA 263:2013: the gross section, and the net section where there are holes. Every step shows its formula and the clause it comes from.
You enter fy,k from table 1 of your copy of SIA 263, for the grade and the plate thickness; every grade drops by 20 to 30 N/mm² once the thickness passes 40 mm. Then the gross area, directly or from the width b and thickness t of a flat bar; whether there are holes in the tension length; γM1 (clause 4.1.3, 1.05); the design tensile force NEd (clause 5.1.2) as a magnitude; and the restrained thermal action: not considered, the upper bound of a fully restrained member, or the force from the global analysis.
You get the gross area, the resistance, the area required, the utilisation with a pass or fail, and the clause of each step. With the Basic plan, it prints as an A4 calculation note.
A flat bar 80 × 12 mm in fy,k = 235 N/mm², with no holes in the tension length, γM1 = 1.05 and a design tensile force of 200 kN, without thermal action. These are the module's own results for its worked example, computed when this page was built.
| Input | Value | Ref. |
|---|---|---|
| Characteristic yield strength fy,k | 235 N/mm² | § t.1 |
| Gross area given by | Flat bar — b × t | § 1.1 |
| Width b | 80 mm | |
| Thickness t | 12 mm | |
| Holes | No holes in the tension length | § 5.1.2.1 |
| Resistance factor, gross section γM1 | 1.05 | § 4.1.3 |
| Design tensile force NEd | 200 kN | § 5.1.2 |
| Imposed axial force from restrained temperature change | Not considered | § 2.3.3 |
| Step | Value | Ref. |
|---|---|---|
| Characteristic yield strength | fy,k = 235 N/mm² | § t.1 |
| Resistance factor, gross section | γM1 = 1.05 | § 4.1.3 |
| Step | Value | Ref. |
|---|---|---|
| Design tensile force | NEd = 200.0 kN | § 5.1.2 |
| Step | Value | Ref. |
|---|---|---|
| Gross areaA = b·t = 80.0 × 12.0 | A = 960 mm² | § 1.1 |
| Plastic axial resistanceNRd = fy,k·A/γM1 = 235 × 960 / 1.05. Every fibre reaches fy,k together under a centred axial force, so the elastic and plastic limits coincide and there is no shape factor to gain. | NRd = 214.9 kN | § (38) |
| Gross area requiredA ≥ γM1·NEd/fy,k, the sizing form of equation (38). | Areq = 894 mm² | § (38) |
| Step | Value | Ref. |
|---|---|---|
| Design resistanceEquation (38) alone; with no hole there is no net section to check. | NRd = 214.9 kN | § 5.1.2.1 |
| Tensile resistance of the sectionNEd ≤ NRd | η = 0.931 · Pass93 % of the capacity used | § 5.1.2.1 |
Verified clause by clause against SIA 263:2013 and against independent calculations used on real projects, before release.
Classification guards against local buckling of compressed plates. A section in tension has no compressed part, so it carries its full resistance whatever its class in compression.
Whenever there is a hole in the tension length. Equation (39) carries fu, γM2 and the factor 0.9, so one bolt hole can make it decisive.
The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.
Norm: SIA 263:2013 · Page updated: 27 October 2026