Structural Engineering Tools

Cold-formed lipped channel under bending and axial force to SIA 263

Checks a cold-formed lipped channel under a moment about its major axis and an axial force in compression or tension, on its effective section with distortional buckling of the flange and lip, to SIA 263:2013. Every step shows its formula and the clause it comes from.

Pro SIA 263:2013

Part of the Pro plan

This module is included in the Pro plan and above, with its calculation note.

About this check

clauses, worked example and questions

Checks a cold-formed lipped channel under a moment about its major axis and an axial force in compression or tension, on its effective section with distortional buckling of the flange and lip, to SIA 263:2013. Every step shows its formula and the clause it comes from.

What it checks

  • Class of each flat, with ε = √(235/fy): the web and the compressed flange as internal flats (table 5a), the lip as an outstand (table 5b), on the mid-line dimensions hp = h − t, bp = b − t and cp = c − t/2.
  • Edge stiffener, EN 1993-1-3 5.5.3.2: the flange with the lip taken as rigid (k = 4.0), the lip with kσ by (5.13b), then As and Is.
  • Distortional buckling: the spring stiffness K of the web, (5.10b); σcr,s = 2 · √(K · E · Is)/As, (5.15); λ̄d = √(fy/σcr,s); and χd by (5.12), giving tred = χd · t.
  • Effective section in bending, at σmax = fy: zeff by iteration and Weff, the smaller of Weff,c and Weff,t.
  • Effective section in compression, EN 1993-1-3 6.1.3: every flat at fy,k, both stiffeners compressed; Aeff and βA = Aeff/A.
  • Shift of the effective centroid eN, EN 1993-1-3 6.1.9, adding ΔMz,Ed = NEd · eN.
  • Resistances, clause 4.1.3: Nc,Rd and MRd from Aeff and Weff at fy,k/γM1; Mz,Rd from Wz,eff.
  • Flexural buckling about both axes, clause 4.5.1, curve b, on Aeff, with √βA in the slenderness λ̄K.
  • Check 1, section, EN 1993-1-3 6.1.9: NEd/Nc,Rd + My,Ed/MRd + ΔMz,Ed/Mz,Rd ≤ 1.
  • Check 2, stability: NEd/NK,Rd plus the moment terms amplified by 1/(1 − NEd/Ncr,y) and 1/(1 − NEd/Ncr,z).

What you enter and what you get

You enter fy,k (table 1), E (clause 2.2), the out-to-out depth h, flange width b and lip length c, the core thickness t, γM1 (clause 4.1.3), the sense of the axial force, NEd, the largest moment My,Ed and the moment diagram. For buckling, the length l with the end conditions and the intermediate supports ny and nz in each plane, or the buckling lengths directly.

You get the stiffener values, both effective sections, the resistances and the two utilisations with a pass or fail. With the Pro plan, it prints as an A4 calculation note.

Assumptions and limits

  • SIA 263 refers to SN EN 1993-1-3 for thin-walled members; those rows name the EN clause.
  • The lip works best between 0.2 and 0.6 of the flange width.
  • ω = 0.6 + 0.4 · Mmin/Mmax, at least 0.4, for end moments only; otherwise ω = 1.0. No shape factor ξ.
  • Under tension the member checks fall away, since the tension would stabilise the member.
  • The member is assumed held against twist, by the sheeting or by pairing the channels. Lateral-torsional, torsional and flexural-torsional buckling are not checked.
  • Not covered: shear and web crippling at the supports, the fixings, deflection and the construction stage.

Worked example

A lipped channel 200 × 70 × 20 × 2 mm with fy,k = 350 N/mm² and γM1 = 1.05, 4,000 mm long and pinned at both ends, with three intermediate supports about z, under a compression of 25 kN and a moment of 5.0 kNm from a transverse load. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Characteristic yield strength fy,k350 N/mm²§ t.1
Modulus of elasticity E210000 N/mm²§ 2.2
Overall depth h200 mm
Flange width b70 mm
Lip length c20 mm
Thickness t2 mm
Resistance factor γM11.05§ 4.1.3
The axial force isCompression
Design axial force NEd25 kN
Largest moment about y along the member My,Ed5.0 kN·m
Moment diagramTransverse load between the ends — ω = 1,0
Buckling lengthsFrom the end conditions and intermediate supports
Length of the member l4000 mm
Ends, buckling about the strong axis yHeld against sway — both ends pinned
Intermediate supports against buckling about y ny0
Ends, buckling about the weak axis zHeld against sway — both ends pinned
Intermediate supports against buckling about z nz3
Calculation: Common values
StepValueRef.
Characteristic yield strengthfy,k = 350 N/mm²§ t.1
Reduction factorε = √(235/fy)ε = 0.8194§ t.5a
Edge stress for the effective widthsfy: the ultimate check, the most compressed fibre at yield. Not asked for.σmax = 350 N/mm²
ThicknessUsual range 1.0 to 5.0 mm for a cold-formed profile, within a base material range of 0.5 to 5.0 mm.t = 2.00 mm
HeightUsual range 80 to 250 mm for a cold-formed profile.h = 200.0 mm
Web — mid-line heighth − thp = 198.0 mm
Flange — mid-line widthb − tbp = 68.0 mm
Lip — mid-line lengthc − t/2cp = 19.0 mm
Web — slendernessMid-line flat width 198.0 mm, internal (held along both edges), in bending. Class limits 59.0 · 68.0 · 101.6 — class 3.b/t = 99.0§ t.5a
Top flange — slendernessMid-line flat width 68.0 mm, internal (held along both edges), compressed. Class limits 27.0 · 31.1 · 34.4 — class 3.b/t = 34.0§ t.5a
Top lip — slendernessMid-line flat width 19.0 mm, outstand (one edge free), compressed. Class limits 7.4 · 8.2 · 11.5 — class 3.b/t = 9.5§ t.5b
Section classEvery compressed flat is within the class 3 limit, so the whole section works elastically — unusual for a cold-formed element.– = Class 3§ t.5a
Calculation: Common values — the effective section
StepValueRef.
Compressed flange — effective width (lip taken as rigid)k = 4,0, λp = 0.730 ≤ 0,9: the whole flange works.beff = 68.0 mm
Lip — buckling coefficientkσ = 0,5 for cp/bp ≤ 0,35, else 0,5 + 0,83·∛((cp/bp − 0,35)²); here cp/bp = 0.279.kσ = 0.500EN 1993-1-3 (5.13b)
Lip — effective widthλp = 0.577 ≤ 0,9: the whole lip works.ceff = 19.0 mm
Edge stiffener — effective areaAs = t·(be2 + ceff): the flange strip next to the lip and the effective lip.As = 106.0 mm²EN 1993-1-3 5.5.3.2
Edge stiffener — second moment of areaAbout its own centroidal axis parallel to the flange.Is = 3,366 mm⁴EN 1993-1-3 5.5.3.2
Spring stiffness given by the webK = E·t³/(4(1 − ν²))·1/(b1²·hw + b1³), with b1 = 57.1 mm from the web to the stiffener centroid and the other flange in tension. It is how strongly the web holds the flange-and-lip against rotating.K = 0.5550 N/mm²EN 1993-1-3 (5.10b)
Distortional critical stressσcr,s = 2·√(K·E·Is)/As — the stiffener buckling as a strut on the elastic foundation the web provides.σcr,s = 373.7 N/mm²EN 1993-1-3 (5.15)
Distortional slenderness√(fy/σcr,s)λ̄d = 0.968EN 1993-1-3 5.5.3.1
Distortional reduction factor1,0 up to λ̄d = 0,65; 1,47 − 0,723·λ̄d up to 1,38; 0,66/λ̄d beyond. The stiffener is then counted with the thickness tred = χd·t = 1.541 mm.χd = 0.770EN 1993-1-3 (5.12)
Web — effective widthψ = -0.887, k = 21.080, σcr,P = 408.2 N/mm², λp = 0.926. Winter, on the compressed width 104.9 mm: 82.3 % of it works, in two equal parts at the ends of the compressed zone.beff = 86.4 mm
Neutral axis of the gross section, from the bottom mid-linezG = 99.00 mm
Neutral axis of the effective sectionMoved by 5.94 mm away from the compressed side. Found by iteration — the effective widths depend on the stress distribution, which depends on the axis: 7 rounds here.zeff = 93.06 mm
Gross areaA = 744 mm²
Effective area91.7 % of the gross area works.Aeff = 683 mm²
Second moment of area, grossI = 4,570,760 mm⁴
Second moment of area, effectiveIeff = 4,242,124 mm⁴
Elastic section modulus, grossThe smaller of the two extreme fibres.Wel = 45,708 mm³
Effective modulus, compressed sideIeff over the distance from the effective axis to the outer face of the compressed side.Weff,c = 40,044 mm³
Effective modulus, tensioned sideWeff,t = 45,098 mm³
Effective section modulusThe smaller of the two: 87.6 % of the gross elastic modulus. The plastic reserve of the tension zone is not counted.Weff = 40,044 mm³
Calculation: Common values — the effective section in compression
StepValueRef.
Web — effective width in compressionInternal, ψ = 1, k = 4.000, λp = 2.126. 42.2 % of it works.beff,N = 83.5 mm
Flanges and lips — edge stiffeners, both compressedFlange λp = 0.730, lip λp = 0.577.beff · ceff = 68.0 · 19.0 mm
Edge stiffener — spring stiffness of the webBoth flanges compressed: K = E·t³/(4(1 − ν²))·1/(b1²·hw + b1³ + 0,5·b1²·hw), b1 = 57.1 mm.K = 0.3999 N/mm²EN 1993-1-3 (5.10b)
Edge stiffener — elastic critical stress2·√(K·E·Is)/As.σcr,s = 317.2 N/mm²EN 1993-1-3 (5.15)
Distortional buckling — reductionλ̄d = √(fy,k/σcr,s) = 1.050; the stiffeners are taken with χd·t.χd = 0.7105EN 1993-1-3 5.5.3.1
Effective area in compressionEvery flat compressed at σ = fy,k. 61.0 % of the gross area A = 744 mm² works.Aeff = 454 mm²EN 1993-1-3 6.1.3
Thinness factorβA = Aeff/A.βA = 0.6097
Shift of the effective centroidTowards the flange tips: the channel is symmetric about y only, so losing parts of its flanges moves the centroid across the web. NEd stays at the gross centroid and acts on the effective section with this eccentricity about z.eN = 4.68 mmEN 1993-1-3 6.1.9
Additional moment about zNEd·eN.ΔMz,Ed = 0.1170 kN·mEN 1993-1-3 6.1.9
Effective modulus about z, section in compressionIz of the effective section, 300,330 mm⁴, over 25.1 mm from its centroid to the fibre ΔMz compresses: the outer face of the web.Wz,eff = 11,987 mm³
Bending resistance about zfy,k·Wz,eff/γM1.Mz,Rd = 3.996 kN·m
Compression resistance of the effective sectionAeff·fy,k/γM1.Nc,Rd = 151.2 kN§ 4.1.3
Bending resistance of the effective sectionfy,k·Weff/γM1, Weff = 40,044 mm³ — the section in bending alone.MRd = 13.348 kN·m§ 4.1.3
Calculation: Common values — flexural buckling
StepValueRef.
Elastic limit slendernessπ·√(E/fy,k).λE = 76.95
Buckling length, strong axisk·l with k = 1.00.lK,y = 4,000 mm
Relative slenderness, strong axis(lK/i)/λE·√βA, i = 78.4 mm on the gross section: local buckling enters through √βA.λ̄K,y = 0.5178
Buckling resistance, strong axisχK·Aeff·fy,k/γM1, curve b (plain or lipped channel), χK = 0.8762.NK,Rd,y = 132.5 kN§ 4.5.1
Buckling length, weak axisl/(nz + 1).lK,z = 1,000 mm
Relative slenderness, weak axis(lK/i)/λE·√βA, i = 25.7 mm on the gross section: local buckling enters through √βA.λ̄K,z = 0.3948
Buckling resistance, weak axisχK·Aeff·fy,k/γM1, curve b (plain or lipped channel), χK = 0.9281.NK,Rd,z = 140.3 kN§ 4.5.1
Critical load of the section reduced for bendingπ²·E·Ieff/lK,y², Ieff = 4,242,124 mm⁴.Ncr,y = 549.5 kN
Critical load about zπ²·E·Iz/lK,z² on the gross section, Iz = 491,495 mm⁴; it amplifies ΔMz.Ncr,z = 1,018.7 kN
Calculation: Check 1 — section, compression with bending
StepValueRef.
Section, compression with bendingNEd/Nc,Rd + My,Ed/MRd + ΔMz,Ed/Mz,Rd ≤ 1η = 0.569 · Pass57 % of the capacity usedEN 1993-1-3 6.1.9
Calculation: Check 2 — stability, compression with bending
StepValueRef.
Moment factor1,0 for this moment diagram.ω = 1.0000
Amplification factor1/(1 − NEd/Ncr,y) = 1.0477
Axial termThe smaller of the two buckling resistances.NEd/NK,Rd = 0.1887
Moment term, amplifiedNo shape factor ξ: local buckling has taken the plastic reserve of a thin-walled section.(ω·MEd + ΔM)/((1 − NEd/Ncr)·MRd) = 0.3924
Term of ΔMz, amplifiedΔMz,Ed/((1 − NEd/Ncr,z)·Mz,Rd) = 0.0300
Stability, compression with bendingNEd/NK,Rd + amplified moment terms ≤ 1η = 0.611 · Pass61 % of the capacity used

How this module is verified

Verified clause by clause against SIA 263:2013 and against independent calculations used on real projects, before release.

Questions

Why does so much less of the section work in compression than in bending?

The whole web is compressed, and with both flanges compressed the web holds the stiffeners less firmly. In the worked example Aeff falls from 91.7 % of the gross area in bending to 61.0 % in compression, and χd from 0.770 to 0.711.

Is the lip itself checked?

Yes: as an outstand for its class, then through ceff as part of the edge stiffener.

Which plan includes this module?

The Pro plan, with its calculation note.

Related

Norm: SIA 263:2013 · Page updated: 28 October 2026