Open steel section of rectangular plates in torsion to SIA 263

The code governs which inputs appear and how every value is derived.

Member

Material properties, shared by every verification. The cross-section is not shared: SIA 263 classifies it from the internal forces, so it belongs to each verification and appears with it.

About this check

clauses, worked example and questions

Checks the torsional resistance of an open section built of rectangular plates at the ultimate limit state, to SIA 263:2013, with the torsion constant summed element by element and the warping of a double tee as an option. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You enter τy,k from table 1 of your copy of SIA 263, the shape and its dimensions h, b, tw and tf (or each plate), γM1 and the design torsional moment Mx,Ed as a magnitude. For the warping case, only the bar length is added.

You get each element's contribution, K, TR, TRd, τmax and the utilisation with a pass or fail, and a drawing of the section to check against the one you mean. With the Basic plan, it prints as an A4 calculation note.

Assumptions and limits

Worked example

A welded double tee with h = 330 mm, b = 300 mm, tw = 9.5 mm and tf = 16.5 mm in τy,k = 205 N/mm², under Mx,Ed = 20 kNm in uniform torsion; it does not pass the torsional resistance check, with η = 1.71. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Characteristic shear yield strength τy,k205 N/mm²§ t.1
ShapeDouble tee — I or H
Overall depth h330 mm
Flange width b300 mm
Web thickness tw9.5 mm
Flange thickness tf16.5 mm
Resistance factor γM11.05§ 4.1.3
Design torsional moment Mx,Ed20 kNm
WarpingNot considered — uniform torsion only
Calculation: Common values
StepValueRef.
Characteristic shear yield strengthEntered from table 1, not derived.τy,k = 205 N/mm²§ t.1
Resistance factorγM1 = 1.05§ 4.1.3
Overall depthh = 330.0 mm
Overall widthb = 300.0 mm
AreaThe sum of the rectangles of the outline. Exact for a section built of plates; for a ROLLED profile it is short by the root fillets, 4,7 % on an HEA 340.A = 12,722 mm²
Thickest plateDerived from the section rather than entered. The peak shear stress of an open section is Tv·t/K, so it occurs here.tmax = 16.5 mm
Second moment of area about yReported so the section can be recognised. Not used by the torsion check: the plate model is 4,6 % below the tabulated value for Iy, because the fillets sit near the web where they count for Iy and not for Iz.not usedIy = 264,213,316 mm⁴
Element 1 — h/t and βThe mid-line plate is 300.0 × 16.5 mm, so h/t = 18.18, above 10, so β is taken as 1/3.β1 = 0.3333
Element 1 — contributionβ·h·t³K1 = 449,213 mm⁴
Element 2 — h/t and βThe mid-line plate is 300.0 × 16.5 mm, so h/t = 18.18, above 10, so β is taken as 1/3.β2 = 0.3333
Element 2 — contributionβ·h·t³K2 = 449,213 mm⁴
Element 3 — h/t and βThe mid-line plate is 313.5 × 9.5 mm, so h/t = 33.00, above 10, so β is taken as 1/3.β3 = 0.3333
Element 3 — contributionβ·h·t³K3 = 89,596 mm⁴
K with the exact coefficients throughoutTaking β as 1/3 above h/t = 10 is 3.4 % above the exact series here. That rule is followed; this is the size of it.not usedKexact = 955,167 mm⁴
Torsion constantK = Σ βi·hi·ti³, the elements summed because each rotates by the same amount per unit length while keeping its own shape.K = 988,021 mm⁴
Calculation: Check 1 — uniform torsion
StepValueRef.
Governing element — thickesttmax = 16.5 mm
Peak shear stress at Mx,EdThe stress is linear in the torque, so τmax = τy,k·Mx,Ed/TR.τmax = 334.00 N/mm²
Ultimate torsional resistanceTR = τy,k·K/tmax. The flow turns back within the thickness of each plate, so the stress is τv = Tv·t/K and peaks in the THICKEST one.TR = 12.28 kNm
Design torsional resistanceTRd = TR/γM1TRd = 11.69 kNm
Torsional resistance of the open sectionMx,Ed ≤ TRdη = 1.711 · Fail171 % of the capacity used

How this module is verified

Verified clause by clause against SIA 263:2013 and against independent calculations used on real projects, before release.

Questions

Why is K_exact shown if it is not used?

The rule of 1/3 above h/t = 10 overstates K slightly. Kexact shows by how much.

Can I use this module for a rolled I or H section?

Use the rolled-profile module instead. The plate sum leaves out the root fillets, which carry torsion, so it falls short of the tabulated K. Keep this module for angles and welded sections.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 263:2013 · Page updated: 27 October 2026