Reinforced or prestressed concrete tie to SIA 262

The code governs which inputs appear and how every value is derived.

Member

Material properties, shared by every verification. The cross-section is not shared: SIA 262 works from the section as sized for each internal-force case, so it belongs to each verification and appears with it.

About this check

clauses, worked example and questions

Checks a reinforced or prestressed concrete tension member of any section, with bars and prestressing units at their own coordinates, to SIA 262:2025: resistance, cracking, prestress limits, steel stresses and crack width. Every step shows its formula and the clause it comes from.

What it checks

What you enter and what you get

You choose the shape (rectangle, circle, or a polygon drawn by clicking its corners) and click each bar and prestressing unit into the drawing at its real position. You enter the materials, the type of prestressing, fck(t), P0, P∞, the factors γs, γc, γP and ηt, and Nd. For serviceability: the requirement level, wnom from Table 17, the force N and its load case, and the EN crack-width factors.

You get every intermediate value and check with its utilisation and clause, and a drawing of the section. With the Basic plan, it prints as an A4 calculation note.

Assumptions and limits

Worked example

A 400 × 400 mm tie with eight Ø20 bars and one bonded post-tensioned unit of 1,050 mm² at the centre (P0 = 1,300 kN, P∞ = 1,100 kN), under Nd = 2,400 kN and a quasi-permanent N = 1,700 kN, with increased crack requirements and wmax = 0.3 mm. These are the module's own results for its worked example, computed when this page was built.

Inputs
InputValueRef.
Shape of the sectionRectangle
Width b400 mm
Depth h400 mm
Layout of the steel in the section{"b":[[50,50,20],[50,350,20],[200,50,20],[200,350,20],[350,50,20],[350,350,20],[50,200,20],[350,200,20]],"p":200,200,1050,"v":[]}
Mean tensile strength fctm2.9 N/mm²§ 3.1.2.2.4
Mean modulus of elasticity Ecm33600 N/mm²§ 3.1.2.3.3
Characteristic yield strength fyk500 N/mm²
Modulus of elasticity Es205000 N/mm²
Type of prestressingPost-tensioned, grouted (bonded)
Characteristic tensile strength fpk1860 N/mm²
Characteristic 0.1 % proof stress fp0,1k1640 N/mm²
Modulus of elasticity Ep195000 N/mm²
Concrete compressive strength at tensioning fck(t)25 N/mm²§ 4.1.5.2.4
Prestressing force just after tensioning P01300 kN
Effective prestressing force P∞1100 kN
Resistance factor for steel γs1.15§ 2.4.2.6
Resistance factor for concrete γc1.5§ 2.4.2.6
Load factor for prestress γP1.2§ 4.1.5.5.3
Duration factor ηt0.85 — general case§ 4.2.1.3
Design tension force Nd2400 kN
Tensile strength for the cracking forceMean tensile strength (4.4.1.3)§ 4.4.1.3
Requirement levelIncreased§ 4.4.2.2.3
Nominal crack width wnom0.5 mmTable 17
Tension force in the load case N1700 kN
Load case of NQuasi-permanentTable 17
Bond of the bars k1High-bond bars (0.8)EN 1992-1-1 §7.3.4(3)
Duration of the load ktLong-term or repeated (0.4)EN 1992-1-1 §7.3.4(2)
Crack spacing factor for the cover k33.4EN 1992-1-1 §7.3.4(3)
Crack spacing factor for the bond length k40.425EN 1992-1-1 §7.3.4(3)
Bond strength ratio, tendon to bar ξ0.5EN 1992-1-1 §6.8.2
Equivalent diameter of a prestressing unit φp52 mmEN 1992-1-1 §6.8.2(2)
Limiting crack width (optional) wmax0.3 mm
Calculation: Concrete section
StepValueRef.
Gross concrete areab·hAc = 160,000 mm²
Centroid of the concrete(xc ; yc) = (200 ; 200) mm
Smallest dimension of the sectionmin(b ; h)t = 400 mm
Calculation: Steel in the section
StepValueRef.
Reinforcing barsns = 8Ø20
Area of the reinforcing barsΣ π·Ø²/4As = 2,513 mm²
Smallest clear cover of the barsdistance of the bar edge to the nearest facec = 40 mm
Prestressing unitsnp = 1
Area of the prestressing steelΣ Ap,iAp = 1,050 mm²
Concrete area net of the steelAc − As − Apthe duct itself is not deductedAc,n = 156,437 mm²
Eccentricity of the steel centroiddistance between the steel and the concrete centroidses = 0 mm
Calculation: Idealised section
StepValueRef.
Modular ratio of the barsEs/Ecmαs = 6.10
Modular ratio of the prestressing steelEp/Ecmαp = 5.80
Section that carries the prestressAc,n + αs·Asthe prestressing unit is the one pulling, so it is not part of itAc0 = 171,771 mm²
Idealised sectionAc,n + αs·As + αp·ApAci = 177,864 mm²
Calculation: Resistance of the tie
StepValueRef.
Design yield strength of the barsfyk/γsfyd = 434.8 N/mm²§ 2.4.2.5 (4)
Resistance of the barsAs·fydFs,Rd = 1,093 kN
Design strength of the prestressing steelfp0,1k/γsfpd = 1,426.1 N/mm²§ 2.4.2.5 (5)
Resistance of the prestressing steelAp·fpdFp,Rd = 1,497 kN§ 4.1.5.5.1
Design resistance of the tieFs,Rd + Fp,Rdthe concrete takes no tension at the ultimate limit state: it is crackedNRd = 2,590 kN
Calculation: Check 1 — design tension: N_d ≤ N_Rd
StepValueRef.
Design tension against the resistance of the tieNd/NRdη = 0.927 · Pass93 % of the capacity used
Calculation: Check 2 — no brittle failure at cracking: N_cr ≤ N_Rd
StepValueRef.
Cracking force (from the serviceability part)Aci·(fct,eff + P∞/Ac0)Ncr = 1,569 kN§ 4.4.1.3
Resistance above the cracking force (minimum reinforcement)Ncr/NRdη = 0.606 · Pass61 % of the capacity used§ 4.3.1.2
Calculation: Check 3 — concrete at prestress introduction: γ_P·P_0 ≤ N_Rd,c
StepValueRef.
Factor for the brittleness of strong concrete(40/fck(t))^(1/3) ≤ 1ηfc = 1.000§ 4.2.1.2 (26)
Duration factorηt = 0.85§ 4.2.1.3
Design compressive strength at tensioningηfc·ηt·fck(t)/γcfcd = 14.2 N/mm²§ 2.4.2.3 (2)
Design value of the prestressγP·P0Pd = 1,560 kN§ 4.1.5.5.3
Compressive resistance of the concreteAc,n·fcdthe bars in compression are neglected (on the safe side)NRd,c = 2,216 kN
Concrete under the prestress at its introductionPd/NRd,cη = 0.704 · Pass70 % of the capacity used§ 4.1.5.5.3
Calculation: Common values
StepValueRef.
Size factor1/(1 + 0.5·t), t in mkt = 0.833§ 4.4.1.3 (100)
Effective tensile strength of the concretekt·fctmfct,eff = 2.42 N/mm²§ 4.4.1.3 (99)
Concrete stress under the prestress alone−P∞/Ac0compression is negativeσc,∞ = -6.40 N/mm²
Bar stress under the prestress aloneαs·σc,∞σs,∞ = -39.1 N/mm²
Prestressing steel stressP∞/Apσp,∞ = 1,048 N/mm²
Calculation: Decompression and cracking
StepValueRef.
Decompression forceP∞·Aci/Ac0the tension at which the concrete stress returns to zero; the tendon then carries exactly N0N0 = 1,139 kN
Cracking forceAci·(fct,eff + P∞/Ac0)Ncr = 1,569 kN§ 4.4.1.3
Calculation: Just after the first crack (at the crack)
StepValueRef.
Steel strain increase at the crack(Ncr − N0)/(Es·As + Ep·Ap)measured from the state where the concrete strain is zeroεr = 0.597 ‰
Bar stress at the crackEs·εrσs,r = 122.4 N/mm²
Nominal crack width at first crackingσs,r²·Øs/(9·Es·fctm)eq. (102) solved for wnom, with Øs the largest bar (20 mm)wnom,r = 0.056 mm§ 4.4.2.3.4 (102)
Prestressing steel stress at the crackN0/Ap + Ep·εrσp,r = 1,201 N/mm²
Calculation: Check 1 — prestressing steel just after tensioning
StepValueRef.
Prestressing steel stress just after tensioningP0/Apσp,0 = 1,238 N/mm²
Limit just after tensioningmin(0.75·fpk ; 0.85·fp0,1k)σp,lim = 1,394 N/mm²§ 4.1.5.2.2 (22)
Prestressing steel stress after tensioningσp,0/σp,limη = 0.888 · Pass89 % of the capacity used§ 4.1.5.2.2 (22)
Calculation: Check 2 — concrete compression at tensioning
StepValueRef.
Concrete compression just after tensioningP0/Ac0|σc,0| = 7.57 N/mm²
Concrete compression at tensioning|σc,0|/(0.6·fck(t))η = 0.505 · Pass50 % of the capacity used§ 4.1.5.2.4 (23)
Calculation: Check 3 — final prestressing steel stress
StepValueRef.
Final stress after all losses at least 0.45·fpk0.45·fpk/σp,∞η = 0.799 · Pass80 % of the capacity used§ 4.1.5.2.3
Calculation: Check 4 — bar stress when the tie cracks (restrained deformation)
StepValueRef.
Admissible bar stress√(9·Es·fctm·wnom/Øs) ≤ fykØs = largest bar, 20 mmσs,adm = 366 N/mm²§ 4.4.2.3.4 (102)
Bar stress at first crackingσs,r/σs,admη = 0.335 · Pass33 % of the capacity usedTable 17
Calculation: State under N = 1,700 kN
StepValueRef.
State of the sectioncracked (N > Ncr)
Concrete stress at the crack under Nσc = 0 N/mm²
Steel strain increase at the crack under N(N − N0)/(Es·As + Ep·Ap)ε = 0.779 ‰
Bar stress at the crack under NEs·εσs = 159.7 N/mm²
Prestressing steel stress at the crack under NN0/Ap + Ep·εσp = 1,237 N/mm²
Calculation: Check 5 — no yielding of the bars under N
StepValueRef.
Bar stress under N against fyd − 80 N/mm²σs/(fyd − 80)η = 0.450 · Pass45 % of the capacity usedTable 17
Calculation: Check 6 — bar stress under the quasi-permanent N
StepValueRef.
Bar stress under N against the crack limitσs/σs,admη = 0.437 · Pass44 % of the capacity usedTable 17
Calculation: Check 7 — crack width under N (EN 1992-1-1 §7.3.4)
StepValueRef.
Effective tension area around the steelband of depth 2.5·(face to bar axis) along each face with steel, at most half the sectionAc,eff = 137,500 mm²EN 1992-1-1 §7.3.2(3)
Bond factor of the prestressing steel√(ξ·φs/φp)ξ1 = 0.439EN 1992-1-1 §6.8.2 (7.5)
Prestressing steel inside Ac,effAp′ = 0 mm²
Effective reinforcement ratio(As + ξ1²·Ap′)/Ac,effρp,eff = 1.83 %EN 1992-1-1 §7.3.4 (7.10)
Equivalent bar diameterΣn·φ²/Σn·φφ = 20.0 mmEN 1992-1-1 §7.3.4 (7.12)
Cover to the steelsmallest clear cover, from the layoutc = 40 mm
Strain distribution factor (pure tension)(ε1 + ε2)/(2·ε1), ε1 = ε2k2 = 1.0EN 1992-1-1 §7.3.4 (7.13)
Maximum crack spacingk3·c + k1·k2·k4·φ/ρp,effsr,max = 508 mmEN 1992-1-1 §7.3.4 (7.11)
Bar stress used for the crack widthσs = 159.7 N/mm²
Mean strain difference, steel to concrete[σs − kt·fct,eff/ρp,eff·(1 + αe·ρp,eff)]/Es ≥ 0.6·σs/Eskt = 0.4, αe = 6.10, fct,eff of SIA 262 4.4.1.3 used (on the safe side of fctm)εsm − εcm = 0.492 ‰EN 1992-1-1 §7.3.4 (7.9)
Crack widthsr,max·(εsm − εcm)wk = 0.250 mmEN 1992-1-1 §7.3.4 (7.8)
Crack width against the limitwk/wmaxη = 0.834 · Pass83 % of the capacity usedEN 1992-1-1 §7.3.1

How this module is verified

Verified clause by clause against SIA 262:2025 and against independent calculations used on real projects, before release.

Questions

What is the decompression force?

The tension N0 at which the concrete stress returns to zero. The tendon then carries exactly N0.

Why does the prestressing unit not count in the crack width of the example?

Ac,eff is a band of depth 2.5 times the distance from the face to the bar axis along each face with steel, at most half the section (EN 1992-1-1 §7.3.2(3)). The unit at the centre lies outside it, so Ap′ = 0.

Can I print the calculation?

The full calculation is shown on screen, free and without an account. A print-ready A4 calculation note is part of the Basic plan.

Related

Norm: SIA 262:2025 · Page updated: 24 October 2026